Answer and Step-by-step explanation:
<u>Trigonometric Function (These only work for right triangles):</u>
SOH-CAH-TOA
S = Sine = sin
C = Cosine = cos
T = Tangent = tan
O = Opposite (side)
H = Hypotenuse (side)
A = Adjacent (side)
SOH = sin(angle) = 
CAH = cos(angle) = 
TOA = tan(angle) = 
1. sinQ (Q is the angle) = 
Use Pythagorean Theorem to find side PQ. 
2. cosQ = 
3. tanQ = 
Answer: 0.16
Step-by-step explanation:
Given that the run times provided are normally distributed ;
Mean(x) of distribution = 3 hours 50 minutes
Standard deviation(s) = 30 minutes
The probability that a randomly selected runner has a time less than or equal to 3 hours 20 minutes
3 hours 20 minutes = (3 hrs 50 mins - 30 mins):
This is equivalent to :
[mean(x) - 1 standard deviation]
z 1 standard deviation within the mean = 0.84
z, 1 standard deviation outside the mean equals:
P(1 - z value , 1standard deviation within the mean)
1 - 0.8413 = 0.1587
= 0.16
Answer:
a=41.8 BC=2.8
Step-by-step explanation:
sin30/6=sinx/8
8*sin30=6sinx
4=6sinx
sin^-1(4/6)
angle a
cosine rule
bc^2=3^2 +5^2-2(3)(5)*cos30
BC^2=
BC=2.83
2.8
I think it is:
A = 9y = 3yx
A = 9y = 3y (3)
A = 9y = 9y
A = 9y
A/9 = y?
This will come out to 35.1
Hope this helps ya!