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nlexa [21]
2 years ago
13

HELP WITH THESE TWO MATH QUESTIONS PLEASE!!! ASAP!

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
8 0
The first picture would be choice answer c because the number of x's represent how many birds wings are this size. The number on the tic mark represents the size of the wing span. So you would take the number of x's times the tic mark represented under it. There are 3 birds with 3 1/8  wingspan so it wold be 3 1/8 *3. Hoped this helps for the first one!
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Describe the steps that you would use to generate an expression equivalent to 8.1b+6.7a+2.5+7+.9a-2.8b
bija089 [108]

Explanation:

1. Identify the different constellations of variables. Here there are three:

  • b
  • a
  • (none)

2. Combine coefficients of each of the different variable constellations:

  (8.1 -2.8)b +(6.7 +0.9)a +(2.5 +7)

  5.3b +7.8a +9.5

3. Perform any other operations that might be required depending on the sort of equivalent wanted. For example, one could write ...

  5.3(b +(78/53)a) +9.5 . . . . . . . shows the weight of a relative to b

6 0
3 years ago
What is 1+1 please please please
mojhsa [17]
The answer to this question is 2
6 0
2 years ago
Read 2 more answers
What's four and is three correct
tia_tia [17]
Raise 10 to the power of 6 to get 1000000
6 0
3 years ago
Simplify the following
ZanzabumX [31]

Answer:

28∛3+72

Step-by-step explanation:

distribute: 28∛3+24∛3∛9 - be careful, ∛9 is not equal to 3! You are looking for three "copies" of a number since it is a ∛ not √.

28∛3+24∛(3*9)=28∛3+24*3 = 28∛3+72

5 0
2 years ago
The mean per capita income is 15,451 dollars per annum with a variance of 298,116. What is the probability that the sample mean
docker41 [41]

Answer: 0.5467

Step-by-step explanation:

Let X be the random variable that represents the income (in dollars) of a randomly selected person.

Given : \mu=15451

\sigma^2=298116\\\\\Rightarrow\ \sigma=\sqrt{298116}=546

Sample size : n=350

z-score : \dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

To find the probability that the sample mean would differ from the true mean by less than 22 dollars, the interval will be

\mu-22,\ \mu+22\\\\=15,451 -22,\ 15,451 +22\\\\=15429,\ 15473

For x=15429

z=\dfrac{15429-15451}{\dfrac{546}{\sqrt{350}}}\approx-0.75

For x=15473

z=\dfrac{15473-15451}{\dfrac{546}{\sqrt{350}}}\approx0.75

The required probability :-

P(15429

Hence, the required probability is 0.5467.

3 0
3 years ago
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