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2 years ago

Find the quotient 4r ÷ 4s A:4r ÷ s b: 4r ÷ - s c: 4r + s

Mathematics

2 answers:

exis [7]2 years ago

6 0

4r/4s

r/s

Answer none of the above

Mila [183]2 years ago

3 0

Answer:

It would be 4^r-s

Step-by-step explanation:

When u divide these exponets who have to make them divide.

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A baker blends 600 raisins and 400 chocolate chips into a dough mix and, from this, makes 500 cookies. (a) Find the probability

Nina [5.8K]

Answer:

a) P(X = 0) for raisins = 0.33287

b) P(X = 2) for chocolate chips = 0.14379

c) P(X ≥ 2) for both bits = 0.59399

Step-by-step explanation:

The average amount of raisin per cookie is 600/500 = 1.2

The average amount of chocolate chips per cookie = 400/500 = 0.8

a) Using Poisson's distribution function

P(X = x) = (e^-λ)(λˣ)/x!

For raisin, Mean = λ = 1.1

x = 0

P(X = 0) = (e⁻¹•¹)(1.1⁰)/(0!) = 0.33287

b) Using Poisson's distribution function

P(X = x) = (e^-λ)(λˣ)/x!

For chocolate chips, Mean = λ = 0.8

x = 2

P(X = 2) = (e⁻⁰•⁸)(0.8²)/(2!) = 0.14379

c) the probability that a randomly chosen cookie will have at least two bits (raisins or chips) in it.

For this, the average number of bit in a raisin = (600+400)/500 = 2 bits per raisin.

P(X ≥ 2) = 1 - [P(X = 0) + P(X = 1)]

For P(X = 0)

P(X = x) = (e^-λ)(λˣ)/x!

Mean = λ = 2

x = 0

P(X = 0) = (e⁻²)(2⁰)/(0!) = 0.13534

For P(X = 1)

P(X = x) = (e^-λ)(λˣ)/x!

Mean = λ = 2

x = 1

P(X = 1) = (e⁻²)(2¹)/(1!) = 0.27067

P(X ≥ 2) = 1 - [P(X = 0) + P(X = 1)]

P(X ≥ 2) = 1 - (0.13534 + 0.27067) = 1 - 0.40601 = 0.59399

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3 years ago

(Zoom in) I’m just typing cause it needs to b 20 characters long.

Romashka [77]

Answer:

Step-by-step explanation:

ABC is congruent to GEF. The transformation made was reflecting over the origin.

<h2>I'm always happy to help :)</h2>

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3 years ago

In circle Y, what is m?<br><br> 82°<br> 100°<br> 106°<br> 118°

Zielflug [23.3K]

Not sure. If you put the picture up, I could help you

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3 years ago

Help me please. good day

Vladimir79 [104]

Answer:

A. 8

Step-by-step explanation:

you do 8/25 and it gives you 0.32

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3 years ago

The circle is inscribed in Triangle AEC. Which are congruent line segments

Harlamova29_29 [7]

Answer:

E-F and E-D

C-B and C-D

Step-by-step explanation:

The circle and triangle are as shown. The options are:

A-B and C-B
E-F and E-D
E-D and C-D
A-F and E-F
C-B and C-D

By drawing radius lines from the center of the circle to the tangent points B, D, and F, we can divide the triangle into 3 kites. Therefore, only segments that are legs of the same kite are congruent. So the answer must be E-F and E-D, and C-B and C-D.

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3 years ago

Read 2 more answers