The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

$[(n - 1)\times S^{2} / X^{2} \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2} / X^{2} 1- \alpha/2, n- 1 ]$

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

$X^{2}_{[\alpha/2, n - 1]} = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401$

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0

2 years ago

Someone please help me

bearhunter [10]

B. triangle and triangular prism

6 0

2 years ago

NEED HELP ASAP!!! Will give brainliest!!!

Gekata [30.6K]

Answer:

1, 4/5,2/5

Step-by-step explanation:

y = 5x

Let y = 5

5 = 5x

Divide by 5

5/5 =5x/5

1=x

Let y=4

4 =5x

Divide by 5

4/5 =5x/5

4/5 =x

Let y=2

2 =5x

Divide by 5

2/5 =5x/5

2/5 =x

5 0

3 years ago