All categories

3 years ago

Describe the transformation from the graph of y = 1/x to the

Mathematics

1 answer:

tiny-mole [99]3 years ago

5 0

5 units up.

Step-by-step explanation:

Not much explanation needed, it is the same exact graph but with +5 on the Y axis.

You might be interested in

Simplify (-2x^4y^-3)^4

elixir [45]

Answer:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = \frac{16 {x}^{16}}{ {y}^{12} }$

Step-by-step explanation:

We want to simplify:

$( - 2 {x}^{4} {y}^{ - 3} )^{4}$

We need to apply the exponential property for products of powers.

Recall that:

$( {a}^{m} \times {a}^{n} )^{p} = {a}^{mp} \times {a}^{np}$

We apply this rule to get:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = ( { - 2)}^{4} x \times {x}^{16} \times {y}^{ - 12}$

This simplifies to:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = 16 {x}^{16} \times {y}^{ - 12}$

We rewrite as positive index to get:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = \frac{16 {x}^{16}}{ {y}^{12} }$

7 0

3 years ago

Divide (24x^2-16x+18)÷(4x+2)

Aleksandr [31]

Answer:

6x-7+32/4x+2

Step-by-step explanation:

Divide using polynomial division

3 0

3 years ago

Determine the arithmetic sequence if the fourth term is negative six and the eleventh term is negative thirty four

ICE Princess25 [194]

An arithmetic sequence takes the form

$a_n=a_{n-1}+d$

where $d$ is the common difference between terms. You can solve for $a_n$ in terms of any of the previous terms of the sequence:

$a_n=a_{n-1}+d\implies~a_n=a_{n-2}+2d\implies~a_n=a_{n-3}+3d\implies\cdots\implies~a_n=a_{n-k}+kd$

for some integer $1\le k\le n-1$

Continuing in this way, you know that the sequence can be defined explicitly in terms of the first term $a_1$

$a_n=a_1+(n-1)d$

Given that the 4th term is $a_4=-6$ and the 11th term is $a_{11}=-34$ , you have the following system of equations.

$\begin{cases}-6=a_1+(4-1)d\\-34=a_1+(11-1)d\end{cases}$

Solving this system for the two unknowns yields $a_1=6$ and $d=-4$ .

So, the sequence is given explicitly by

$a_n=6+(n-1)(-4)=-4n+5$

3 0

3 years ago

Are these parallel, perpendicular, or neither?

Elina [12.6K]

Answer: I think it’s neither

Explanation:

The line is parallel unless the slope is the same and with a different y-intercept

The line are perpendicular unless the one of the slope is the negative reciprocal of the other.

And both equation didn’t meet any of the requirement.

5 0

3 years ago

Will give brainlyest if u help

goblinko [34]

Answer:

No, because it fails the vertical line test ⇒ B

Step-by-step explanation:

To check if the graph represents a function or not, use the vertical line test

Vertical line test: Draw a vertical line to cuts the graph in different positions,

if the line cuts the graph at just one point in all positions, then the graph represents a function

if the line cuts the graph at more than one point in any position, then the graph does not represent a function

In the given figure

→ Draw vertical line passes through points 2, 6, 7 to cuts the graph

∵ The vertical line at x = 2 cuts the graph at two points

∵ The vertical line at x = 6 cuts the graph at two points

∵ The vertical line at x = 7 cuts the graph at one point

→ That means the vertical line cuts the graph at more than 1 point

in some positions

∴ The graph does not represent a function because it fails the vertical

line test

7 0

3 years ago