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Serggg [28]
3 years ago
8

Joanna went school supply shopping. She spent $30.70 on notebooks and pencils. Notebooks cost $2.20 each and pencils cost $1.09

each. She bought a total of 19 notebooks and pencils. How many of each did she buy?
Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0

Ok, so we need to set up a system of equations.

x + y = 19, where x is notebooks and y is pencils

2.2x + 1.09y = 30.70. You use the coefficient for individual prices and the total for the total given.

2.2x + 2.2y = 41.8  (multiply for elimination later)

2.2x + 1.09y = 30.7

1.11y = 11.1

y = 11.1/1.11

y = 10

Now we use the substitution method in x + y = 19

x + 10 = 19

x = 9

9 notebooks and 10 pencils


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Would assume the Polygon is an 18 sided regular polygon.

Exterior angle for regular polygon = 360/n      (Sum of angles of exterior angles = 360°)

where n = number of sides.

Exterior angle = 360 / 18 = 20

Exterior angle = 20°

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Interior angle = 180° - 20°

Interior angle = <span>160°

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If a 42.9 foot tall flagpole casts a 253.1 foot long Shadow then how long is a shadow that 6.2 foot tall woman casts
soldi70 [24.7K]
The women's shadow would be 36.6ft. long. 
You have to set up a proportion   42.9             6.2
                                                       ---------   =   ------------ 
                                                        253.1               X
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5 0
3 years ago
What is the gcf of 48m^5n and 81m^2n^2
JulijaS [17]

Answer:

gcf is 3m^2n

Step-by-step explanation:

we are given

48m^5n and 81m^2n^2

Firstly, we will find factors of both expression

48m^5n=2\times 2\times2\times 2\times 3\times m^2\times m^3\times n

81m^2n^2=3\times 3\times 3\times 3\times m^2\times n\times n

now, we will find common factors among them

we can see that

For finding gcf, we always find common factors

so,

common terms are 3,m^2 and n

so, gcf is

=3\times m^2\times n

=3m^2n


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