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solong [7]
3 years ago
9

Given the function h(x)=x2+6x+6h(x)=x^2+6x+6h(x)=x2+6x+6, determine the average rate of change of the function over the interval

−7≤x≤2-7\le x \le 2−7≤x≤2.
Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer:

<h2>The answer is -11.</h2>

Step-by-step explanation:

The function is given by h(x) = x^{2} - 6x + 6.

Rate of change refers to the ratio between the change of the dependent variable with the change of independent variable.

The minimum value of x is -7 and the maximum value is 2.

h(-7) = 49 + 42 + 6 = 97.

h(2) = 4 - 12 + 6 = -2.

The average rate of change is \frac{h(-7) - h(2)}{-7 - 2} = \frac{97 + 2}{-9} = -11.

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Which of the following is a perfect square trinomial?
marissa [1.9K]

Answer:

a. x² + 10x + 25

Step-by-step explanation:

because

(x + 5)² = (x + 5)(x + 5) = x² + 5x + 5x + 25 = x² + 10x + 25

so, it is a perfect square of (x + 5).

4 0
2 years ago
How to solve this equation?
Novay_Z [31]

Answer:

x = √(28), or x = 5.292

Step-by-step explanation:

First you distribute the square to the values inside of the parentheses. so it ends up looking like this

5(x^2 - 25) - 9 = 6

add 9 to both sides

so its 5(x^2 - 25) = 15

Then distribute the multiplication of 5 to the contents within the parentheses

so it would be 5x^2 - 125 = 15

add 125 to both sides

you get 5x^2 = 140

divide by 5 on both sides

you get x^2=28

then, take the square root of both sides to reverse the square

√(x^2)=√(28)

and in the end you get x=5.292

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6 0
3 years ago
Through: (1,-1), parallel to y = -3
zheka24 [161]

Answer:

The equation of a line parallel to the line and passing through (1, -1) is:

  • y=-3x+2

Step-by-step explanation:

Given the line

y = -3

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept

Thus, the slope of the equation y=-3 will be m = -3

We know that the parallel lines have the same slopes.

Thus, the slope of the parallel line will also be -3.

Thus, using the point-slope form to find the line equation is

y-y_1=m\left(x-x_1\right)

substituting the values m = -3 and the point (1, -1)

y-(-1) = -3(x-1)

y+1 = -3x+3

y=-3x+3-1

y=-3x+2

Thus, the equation of a line parallel to line and passing through (1, -1) is:

  • y=-3x+2
8 0
3 years ago
Solve cach equation.<br> 2) -2 - 1+"<br> 5
valentinak56 [21]

Answer:

2 - 1+5=6

Step-by-step explanation:

6 0
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