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Nata [24]
3 years ago
15

Find" r". Round to the nearestwhole number.R = 1,750F= 63.2W = 148r=R-2RF/W​

Mathematics
1 answer:
Anika [276]3 years ago
3 0

r = 255

r = R-2RF/W

R = 1,750

F = 63.2

W = 148

Now, we need to plug the values in to substitute the variables with real numbers.

r = 1750-2(1750 x 63.2)/148

First, solve for the parentheses.

r = 1750-2(110600)/148

Second, multiply by 2.

r = 1750-221200/148

Next, divide by 148.

r = 1750 - 1494.594

Then, we subtract.

r = 255.406

Lastly, we round it to the nearest whole number.

r = 255

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Step-by-step explanation:

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We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
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the price of a dress is $40.00. it went to sale at a discount of 25%. if the sales tax is 6% what is the final cost of the dress
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sveticcg [70]

Answer:

5x^2+22x-12         x cannot be -5, -4, -2

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Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)

Now that you have factored out the two quadratics, plug them into the equation.

    5x        -       3

(x+4)(x+2)      (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5)             -           3(x+4)  

(x+5)(x+4)(x+2)      (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

5x^2+25x - (3x+12)     =    5x^2+22x-12         x cannot be -5, -4, -2

 (x+5)(x+4)(x+2)               (x+5)(x+4)(x+2)

4 0
2 years ago
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