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Radda [10]
3 years ago
10

12x+7<-11 or 5x-8>40

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

A

Step-by-step explanation:

Given

12x + 7 < - 11 or 5x - 8 > 40

Solve each inequality

12x + 7 < - 11 ( subtract 7 from both sides )

12x < - 18 ( divide both sides by 12 )

x < - \frac{3}{2}

OR

5x - 8 > 40 ( add 8 to both sides )

5x > 48 ( divide both sides by 5 )

x > \frac{48}{5}

Solution is

x < - \frac{3}{2} or x > \frac{48}{5} → A

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