3 years ago

12x+7<-11 or 5x-8>40

Mathematics

1 answer:

DaniilM [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Given

12x + 7 < - 11 or 5x - 8 > 40

Solve each inequality

12x + 7 < - 11 ( subtract 7 from both sides )

12x < - 18 ( divide both sides by 12 )

x < - $\frac{3}{2}$

5x - 8 > 40 ( add 8 to both sides )

5x > 48 ( divide both sides by 5 )

x > $\frac{48}{5}$

Solution is

x < - $\frac{3}{2}$ or x > $\frac{48}{5}$ → A

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