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3 years ago

A city has a 5% sales tax.

Mathematics

1 answer:

Tcecarenko [31]3 years ago

8 0

Answer:

Yes,

There is a direct proportional relationship between the cost of items before tax and the cost of items after tax.

Step-by-step explanation:

Given - A city has a 5% sales tax.

To find - Is there a proportional relationship between the cost of items

before tax and the cost of items after tax?

Proof -

Yes, cost of items before tax is directly proportional to cost of items after tax.

Reason -

With the increase in the sales tax, there is increase in the cost of items after tax, therefore, there is a direct relation between cost of items before tax and cost of items after tax.

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Consider the gender and class make-up of students at a large university by gender and status as given in the table.

azamat

Answer:

0.589

Step-by-step explanation:

THis is a conditional probability question. Let's look at the formula first:

P (A | B) = P(A∩B)/P(B)

" | " means "given that".

So, it means, the "Probabilty A given that B is equal to Probability A intersection B divided by probability of B."

So we want to know P (Female | Undergraduate ). This in formula is:

P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)

Now,

P (Female ∩ Undergraduate) means what is common in both female and undergraduate? There are 43% female that are undergrads. Hence,

P (Female ∩ Undergraduate) = 0.43

Also,

P (Undergraduate) is how many undergrads are there? There are 73% undergrads, so that is P (undergraduate) = 0.73

plugging into the formula we get:

P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)

=0.43/0.73 = 0.589

this is the answer.

4 0

4 years ago

Please please help me out

cricket20 [7]

Answer:

B is the correct answer

3 0

3 years ago

A recent study in a small city stated that the average age of robbery victims was 63.5 years. A random sample of 20 recent victi

Elina [12.6K]

Answer:

The p-value of the test is of 0.3219 > 0.05, which means that at $\alpha = 0.05$ , the average age is not higher than originally believed.

Step-by-step explanation:

A recent study in a small city stated that the average age of robbery victims was 63.5 years. Test if the average age higher than originally believed.

At the null hypothesis, we test that the mean is the believed mean age of 63.5 years, that is:

$H_0: \mu = 63.5$

At the alternate hypothesis, we test if this mean is higher, that is:

$H_1: \mu > 63.5$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

63.5 is tested at the null hypothesis:

This means that $\mu = 63.5$

A random sample of 20 recent victims had a mean of 63.7 years and a standard deviation of 1.9 years.

This means that $n = 20, X = 63.7, s = 1.9$

Test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{63.7 - 63.5}{\frac{1.9}{\sqrt{20}}}$

$t = 0.47$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 63.7, which is a right-tailed test, with t = 0.47 and 20 - 1 = 19 degrees of freedom.

With the help of a calculator, this probability is of 0.3219.

The p-value of the test is of 0.3219 > 0.05, which means that at $\alpha = 0.05$ , the average age is not higher than originally believed.

5 0

3 years ago

The battery standby duration (in hours) of a new model of cell phone is known to be normally distributed. Ten pieces of such new

kap26 [50]

Answer:

$\mu = 47.17$

$\sigma = 2.31$

Step-by-step explanation:

Solving (a): The population mean

This is calculated as:

$\mu = \frac{\sum x}{n}$

So, we have:

$\mu = \frac{48.2+ 47.8 +45.6 +47.2 +49.3+51.2 +44.2 +45.4 +49.2 +43.6}{10}$

$\mu = \frac{471.7}{10}$

$\mu = 47.17$

Solving (b): The population standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum (x - \mu)^2}{n}}$

So, we have:

$\sigma = \sqrt{\frac{(48.2-47.17)^2 + (47.8-47.17)^2 +.........+(43.6-47.17)^2}{10}}$

$\sigma = \sqrt{\frac{53.521}{10}}$

$\sigma = \sqrt{5.3521$

$\sigma = 2.31$

4 0

3 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

son4ous [18]

Answer:

Step-by-step explanation:

The orthocenter of a triangle is the point of intersection of the three altitudes of the triangle.

In an obtuse triangle, two altitudes are completely outside the triangle; therefore, the three altitudes cannot possibly intersect inside the triangle.

Answer: B

8 0

3 years ago