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Oliga [24]
3 years ago
7

How was abcdefgh transform to a'b'c'd'e'g'h'

Mathematics
2 answers:
strojnjashka [21]3 years ago
8 0
It reflects across the x axis
Gennadij [26K]3 years ago
6 0

Answer:

dilated by a scale factor of 3

Step-by-step explanation:

idk i just want the points

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Pls help me. It due ASAP...
Bad White [126]

Answer:

b

Step-by-step explanation:

8 0
2 years ago
2,5, 25/2, ... <br> find the 10th term
notka56 [123]

Answer:

The  10^{th} term of the given sequence

t_{10} = \frac{5^{9} }{2^{8} }

Step-by-step explanation:

<u>Step(i):-</u>

Given sequence   2 , 5, \frac{25}{2}

First term    a = 2

The difference of given geometric sequence

    d = \frac{r_{2} }{r_{1} } = \frac{5}{2}

<u><em>Step(ii):-</em></u>

The  n^{th} term of the given sequence

t_{n} = ar^{n-1}

The  10^{th} term of the given sequence

t_{10} = (2)(\frac{5}{2} )^{10-1}

t_{10} = (2)(\frac{5}{2} )^{9}= \frac{5^{9} }{2^{8} }

8 0
3 years ago
Need help ASAP will mark brainliest
nalin [4]

Answer:

  5x -7y = 21

Step-by-step explanation:

A sketch can convince you that BC is a transversal perpendicular to parallel lines AB and CD. The question asks for an equation for CD, so we just need to write the equation of a line through D that is parallel to AB.

One way to do this is to equate the slopes of the parallel lines:

  ∆y/∆x for AB = ∆y/∆x for CD

  (y2 -y1)/(x2 -x1) = (y -2)/(x -7) . . . . . . where (x1, y1) = A; (x2, y2) = B; (7, 2) = D

  (4 -(-1))/(1 -(-6)) = (y -2)/(x -7)

  5(x -7) = 7(y -2) . . . . . . . . . . . . . cross multiply

  5x -7y = 21 . . . . . . . . . . . . . . . . add 35 -7y, simplify

_____

Note that the graph shows the line CD is named "b", and its equation is shown at upper left. Multiplying that equation by -1 gives the one shown here.

6 0
3 years ago
Fill the blank bellow.....
Lemur [1.5K]

slope = (y2-y1)/(x2-x1)

the first slope is 0 (horizontal line)

second slope is undefined (vertical line)

3 0
3 years ago
What is the value of x in this proportion?
astra-53 [7]

Answer:

  (a)  x=−20 1/2

Step-by-step explanation:

Multiply by the product of the denominators and solve the resulting linear equation in the usual way.

  \dfrac{2}{7}=\dfrac{-5}{x+3}\\\\2(x+3)=-5(7)\qquad\text{multiply by $7(x+3)$}\\\\2x+6=-35\qquad\text{simplify}\\\\2x=-41\qquad\text{subtract 6}\\\\\boxed{x=-20\dfrac{1}{2}}\qquad\text{divide by 2}

6 0
2 years ago
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