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3 years ago

Determine if the function f is an exponential function. If so, identify the base. If not, why not?

Mathematics

1 answer:

pishuonlain [190]3 years ago

8 0

Answer: D) The base is e^(-1)

We use the rule that x^(-k) = 1/(x^k). That allows us to say e^(-1) = 1/(e^1) = 1/e

The 1/e is the base of the exponential (1/e)^x

In general, the exponential b^x has base b.

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Determine the domain of the function h=9x/x(x^2-49)

Juliette [100K]

ANSWER

$( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )$

EXPLANATION

The given function is

$h(x) = \frac{9x}{x( {x}^{2} - 49) }$

This function is defined for values where the denominator is not equal to zero.

$x( {x}^{2} - 49) \ne0$

$x(x - 7)(x + 7) = 0$

The domain is

$x \ne - 7, x \ne0, \: and \: x \ne 7,$

$( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )$

8 0

3 years ago

Mike rides his horse with a constant speed of 14 km/h. How far can he travel in 3 1/2 hours?

Andreyy89

Answer:

126 km/h

Step-by-step explanation:

Sorry if I'm wrong:/

8 0

3 years ago

What is the midpoint of RS with endpoints R (-8, 3) and S (9, – 7)?

lubasha [3.4K]

Answer:

Midpoint coordinates are $(x,y) = (\frac{1}{2} , -2)$

Step-by-step explanation:

The Coordinates of R = (-8,3)

The Coordinates of S = (9, -7)

Let M be the mid point of M and its coordinates by (x,y)

Now, by mid point formula,

$(x,y) = (\frac{x_1 + x_2}{2} ,\frac{y_1 + y_2}{2} )$

⇒ $(x,y) = (\frac{1}{2} ,\frac{-4}{2} ) = (\frac{1}{2} , -2)$

So, the midpoint coordinates are $(x,y) = (\frac{1}{2} , -2)$

8 0

3 years ago

PLS HELP!!!

Anni [7]

Answer:

I think it is either a or b

Step-by-step explanation:

3 0

2 years ago

Evaluate 12 ÷ (-3)(2) + 5-133-3

shepuryov [24]

Solution

The question would like us to evaluate the following:

$12÷-3\left(2\right)+5$

- The solution is given below:

$\begin{gathered} 12\div(-3)(2)+5 \\ \text{ Perform the division first before multiplication because we move from left to right when} \\ division\text{ and multiplication are together} \\ 12\div(-3)=-4 \\ \\ Thus,\text{ we have} \\ 12\div(-3)(2)+5=-4(2)+5 \\ \\ -4(2)+5=-8+5 \\ \\ =-3 \end{gathered}$

Final Answer

The answer is -3

5 0

1 year ago