3 years ago

25 POINTS! MATCHING PROBLEM!

Mathematics

1 answer:

Nataly_w [17]3 years ago

8 0

1. f(x) = 1
2. f(x) = x
3. f(x) = 5 - x
4. f(x) = 3

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Answer:

$\sf x=2+\sqrt{6},\:x=2-\sqrt{6}$

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$\sf x^2 -4x -2 = 0$

using quadratic formula:

$\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ \ when \ ax^2 + bx + c = 0$

$\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}$

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