Katie, Let the number of nickles = N Since there are 7 more dimes than nickles, the number of dimes D = N + 7 Since there are 4 more quarters than nickles, the number of quarters Q = N + 4 Since quarters = $0.25, dimes = $0.10, and nickles = $0.05 and all added together = $4.90 ⇒ 0.25·Q + 0.10·D + 0.05·N = 4.90 Now multiply through by 100 to eliminate the decimal: 25Q + 10D + 5N = 490 Substitute for Q and D 25(N+4) + 10(N+7) + 5N = 490 25N + 10N + 5N +100 +70 = 490 40N + 170 = 490 ⇒ 40N = 320 ⇒ N = 320/40 N = 8, D = N+7 = 15 Q = N+4 = 12 Check: 25(12) + 10(15) + 5(8) = 300 + 150 + 40 = 490
I got the answer as this by simplifying both sides of the equation, then isolating the variable. j=-6
Answer:
p(x) + 10
Step-by-step explanation:
this is a little confusing, but they didnt give a specific number so i used x. hope this helps!
Answer:
59.
Step-by-step explanation:
First replace the x in f(x) by g(x):
(fg)x = 3(2x^2 + 5x) + 5 (Tip: think right to left)
So (fg)(2) = 3(2(2)^2 + 5*2) + 5
= 3(18) + 5
= 54 + 5
= 59.
Bearing in mind that cos(π) is -1, and sin(π) is 0, then
