Answer:
Age of son = 6 years
Age of man = 5×6 = 30 years
Step-by-step explanation:
<u>GIVEN :-</u>
- A man is 5 times as old as his son. (In Present)
- 4 years ago , the man was 13 times as old as his son
<u>TO FIND :-</u>
- The present ages of the man & his son.
<u>SOLUTION :-</u>
Let the present age of son be 'x'.
⇒ Present age of man = 5x
4 years ago ,
Age of son = (Present age of son) - 4 = x - 4
Age of man = (Present age of man) - 4 = 5x - 4
The man was thirteen times as old as his son. So,
![=> 5x - 4 = 13(x - 4)](https://tex.z-dn.net/?f=%3D%3E%205x%20-%204%20%3D%2013%28x%20-%204%29)
Now , solve the equation.
- Open the brackets in R.H.S.
![=> 5x - 4 = 13x - 52](https://tex.z-dn.net/?f=%3D%3E%205x%20-%204%20%3D%2013x%20-%2052)
- Take 5x to R.H.S. and -52 to L.H.S. Also , take care of their signs because they are getting displaced from L.H.S. to R.H.S. or vice-versa.
![=> 13x - 5x = 52 - 4](https://tex.z-dn.net/?f=%3D%3E%2013x%20-%205x%20%3D%2052%20-%204)
![=> 8x = 48](https://tex.z-dn.net/?f=%3D%3E%208x%20%3D%2048)
- Divide both the sides by 8
![=> \frac{8x}{8} = \frac{48}{8}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B8x%7D%7B8%7D%20%3D%20%5Cfrac%7B48%7D%7B8%7D)
![=> x = 6](https://tex.z-dn.net/?f=%3D%3E%20x%20%3D%206)
<u>CONCLUSION :-</u>
Age of son = 6 years
Age of man = 5×6 = 30 years
notice the tickmarks on the sides, meaning TX = FL, YX = FW and YT = WL, I must say those tickmarks are missing a triplet one |||, but anyhow, they are there, and if that is indeed the case, then S ide S ide S ide.
Given:
nine 5 pound bags
distributed into 10-ounce bags
1 pound = 16 ounces
9 x 5 pounds = 45 pounds
45 pounds * 16 ounces/lbs = 45 * 16 oz = 720 ounces
720 ounces / 10 ounce bags = 720/10 = 72 bags.
The workers at the food pantry will be able to make 72 bags.
ANSWER
![\sqrt{13} = 3.606](https://tex.z-dn.net/?f=%20%5Csqrt%7B13%7D%20%20%3D%203.606)
to the nearest thousandth.
EXPLANATION
The given irrational number is
![\sqrt{13}](https://tex.z-dn.net/?f=%20%5Csqrt%7B13%7D%20)
We use the calculator to evaluate this to obtain,
![\sqrt{13} = 3.605551...](https://tex.z-dn.net/?f=%20%5Csqrt%7B13%7D%20%20%3D%203.605551...)
To round to the nearest thousandth means we are rounding to 3 decimal places.
The third decimal place is 5.
The next number is 5 so we round up.
![\sqrt{13} = 3.606](https://tex.z-dn.net/?f=%20%5Csqrt%7B13%7D%20%20%3D%203.606)