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zaharov [31]
3 years ago
7

5/12 x 4/5????????????

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

omeli [17]3 years ago
6 0

Answer:

2/3

Step-by-step explanation:

5/12*4/5=2/3

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Step-by-step explanation:

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3 years ago
In a race, the second place finisher crossed the finish line 1 1/3 minutes after the winner. the third place finisher was 1 3/ m
ss7ja [257]

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Please answer question with work ♥️
vova2212 [387]

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r=201

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r - 25 = 11*16

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r = 11*16 + 25 = 201


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multiply by 5/2

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A cone had a diameter of 6 centimeters and a height that is 5 times the diameter. Using 3.14 for pi, which of the following can
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3 years ago
A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

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\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

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3 years ago
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