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Semmy [17]
3 years ago
15

Sheila went shopping and spent $120 on a coat. She then used 2/3 of the remaining money to buy a dress. She was left with 1/5 ot

her original amount of money. How much did Sheila have at first?
Mathematics
1 answer:
Masja [62]3 years ago
6 0

Answer:

Sheila had $300 at first

Step-by-step explanation:

Given that:

Sheila spent:

for coat = $120

Let the original money be x so,

dress for = $(2/3(x - 120 ))

Now she left with = 1/5x

Now by adding all the amounts we get the original amount x:

x = 120 + (2/3(x - 120)) + 1/5x

By simplifying:

x = 120 +  2/3x - 240/3 + 1/5 x

adding like terms:

x = 120 - 80 + 2/3*5/5x + 1/5*3/3x

x = 40 + (10+3)x/15

x = 40 + 13x/15

x - 13x/15 = 40

Taking LCM

(15x - 13x)/15 = 40

2x/15 = 40

Multiply both sides by 15/2

x = 40*15/2

x = $300

so Sheila had $300 at first

i hope it will help you!

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jeyben [28]

Answer:

The length of the legs is 8.64cm and 14.64cm respectively

Step-by-step explanation:

I've added an attachment to aid my explanation.

At different intervals, I'll be making reference to it.

Given

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w = \frac{-12 \± \sqrt{12^2 - 4 * 2 * -253}}{2 * 2}

w = \frac{-12 \± \sqrt{144 + 2024}}{4}

w = \frac{-12 \± \sqrt{2168}}{4}

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Split:

w = \frac{-12 + 46.56}{4} or w = \frac{-12 - 46.56}{4}

w = \frac{34.56}{4} or w = \frac{-58.56}{4}

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But length can't be negative

So:

w = 8.64

Recall that: x = 6 + w

x = 6 + 8.64

x = 14.64

<em>Hence, the length of the legs is 8.64cm and 14.64cm respectively</em>

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