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4 years ago

8

Solve for a. solve for a. solve for a. solve for a.

1 answer:

suter [353]4 years ago

6 0

Answer:09

Step-by-step explanation:

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Angle C is an inscribed angle of circle P. Angle C measures (x + 5)° and arc AB measures (4x)° . Find x.

erastova [34]

Step-by-step explanation:

$m \angle \: C = \frac{1}{2} (m \: arc \: AB)\\(By\:inscribed \:\angle\:theorem) \\ \\ \therefore \: (x + 5) \degree =\frac{1}{2} (4x)\degree \\ \\ \therefore \: x + 5=\frac{1}{2} \times 4x \\ \\ \therefore \: x + 5=2x \\ \\ \therefore \: x - 2x = - 5 \\ \\ \therefore \: - x = - 5 \\ \\ \: \: \: \: \: \huge \purple{ \boxed{\therefore \: x = 5}}$

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4 years ago

Which of the following terms best fits this definition?

elena-14-01-66 [18.8K]

Step-by-step explanation:

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2 years ago

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AleksAgata [21]

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3 years ago

What is 3 x 1028372910 + 12.

MrMuchimi

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Trigonometry<br> Trigonometric Functions <br> Given: Cos θ = (3/5), Find: Csc θ

nasty-shy [4]

The value of $\csc \theta$ is $\frac{5}{4}$

Explanation:

Given that the function $cos \ \theta$ is $cos \ \theta= \frac{3}{5}$

We need to determine the value of $\csc \theta$

<u>The value of Opposite side of the triangle:</u>

The formula for $cos \ \theta$ is given by

$cos \ \theta= \frac{adj}{hyp}=\frac{3}{5}$

The value of opposite side can be determined using the formula,

$opp=\sqrt{hyp^2-adj^2$

$opp=\sqrt{5^2-3^2}$

$opp=\sqrt{25-9}$

$opp=\sqrt{16}=4$

Thus, the value of opposite side is 4

<u>The value of </u> $\csc \theta$ <u>:</u>

The formula for $\csc \theta$ is given by

$csc \ \theta=\frac{1}{sin \ \theta}$

First, we shall determine the value of $sin \ \theta$

The formula for $sin \ \theta$ is given by

$sin \ \theta= \frac{opp}{hyp}$

Substituting the values, we have,

$sin \ \theta= \frac{4}{5}$

Thus, the value of $sin \ \theta$ is $\frac{4}{5}$

Substituting the values in the formula for $\csc \theta$ , we have,

$csc \ \theta=\frac{1}{\frac{4}{5}}$

$csc\ \theta= \frac{5}{4}$

Hence, the value of $\csc \theta$ is $\frac{5}{4}$

5 0

3 years ago