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liubo4ka [24]
3 years ago
11

Volume scale factor, help needed.

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
I hope this helps you

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I believe this is goodbye i hope i helped u guys.
jeyben [28]

Answer:

goodbye??? what're you going to bed? you alr my dude?

Step-by-step explanation:

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3 years ago
1.) Use the following information to solve the questions. Kay sold 200
Yakvenalex [24]

9514 1404 393

Answer:

  • 75 adult tickets
  • 125 child tickets

Step-by-step explanation:

Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...

  8a +5(200 -a) = 1225

  3a = 225 . . . . . . . . . . subtract 1000, simplify

  a = 75 . . . . . . . . . . . . .divide by 3

  200 -a = 125

75 adult ($8) and 125 child ($5) tickets were sold.

__

<em>Additional comment</em>

The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.

3 0
3 years ago
The area of a rectangular-shaped garden can be no more than 64 square feet. If the length of the garden is 16 feet, what could b
Klio2033 [76]

Answer:

4 square feet

Step-by-step explanation:

Area = Length * Width

64 = 16 * W.

W = 4.

So, 4 square feet.

Mark me as Brainliest if this is correct! I really appreciate it! :D

8 0
3 years ago
The table below shows the combination of a dry prepackaged mix and water to make concrete. The mix says for every 1 gallon of wa
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c25

Step-by-step explanation:

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3 years ago
Read 2 more answers
Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zigmanuir [339]

Answer:

P(E \cup F)=P(E)+P(F).

Step-by-step explanation:

Given the statement

If P(E)+P(F)=P(E \cup F)+P(E \cap F), then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

P(E \cup F)=P(E)+P(F).

3 0
4 years ago
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