First, we subtract 12x from both sides. We then get -4y=-12x+48. We then divide this by -4 on both sides to get the y by itself. We then get that the equation is y=3x-12.
Answer:
Local max is .5
Step-by-step explanation:
The local maximum is for x values between 2 and 4
It looks like the x value is 2.5 and the y value is .5
1. The vertical asymptote requires the denominator have a zero at that location. The x-intercept requires the numerator have a zero at that location. The horizontal asymptote amounts to a multiplier of the function:
... y = 2(x +5)/(x -3)
2. The vertical asymptote requires the denominator have a zero at that location. The oblique asymptote is an add-on
... y = 1/(x +1) +(x +2)
... y = (x² +3x +3)/(x +1)
y-axis = altitude in feet
x-axis = minutes
slope = y/x = feet/minute
According to above data, we know that 1800 feet is y-intercept and slope is -300 feet per minute (why slope is negative? because its approaching ground at a constant speed)
a. slope = -300
y-intercept = 1800
b. y = -300 x + 1800
c. Here we are given x = 2 minutes
y = -300(2) + 1800
y = -600 + 1800
y = 1200
The balloon will be 1200 feet high above the ground in 2 minutes.
d. Here we are given 300 feet which is y, and find x minutes.
y = -300 x + 1800
300 = -300x + 1800
300 - 1800 = - 300x
-1500 = -300x
1500 = 300 x
x = 1500 / 300
x = 5
The balloon will reach 300 feet above the ground in 5 minutes.
e. It asking when the balloon will reach the ground, if the balloon reaches the ground than the height will be 0, therefore x-intercept (y=0).
y = -300 x + 1800
0 = -300 x + 1800
-1800 = -300x
1800 / 300 = x
x = 6
The balloon will reach the ground in 6 minutes.
<em>//Hope this helps</em>
