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raketka [301]
3 years ago
14

Consider the linear equation y = 5x – 4.

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
5 0

Answer:

(0,-4), (2,6), and (4, 16) are solutions to this equation.

Yes the point (-5,-29) is a solutions

Step-by-step explanation:

(-5,-29) is a solution because if you plug in -5 for x, y will equal to the y in the ordered pair.

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How to solve the logarithmic equation.
Anna007 [38]
Using logarithmic laws: log(a) + log(b) = log(ab)

log₄ (x + 9) + log₄ (x + 21) = log₄ [(x + 9)(x + 21)] = 3

Since we want the equation in terms of x, the next intuitive step is take 4 to the power of both sides, because the left hand side will simplify easily.

4^{log_4 (x + 9)(x + 21)} = 4^{3}
(x + 9)(x + 21) = 64
x^{2} + 9x + 21x + 189 = 64

Solving the quadratic we get:
x^{2} + 30x + 125 = 0
(x + 5)(x + 25) = 0

x = -5, -25

BUT, for the logarithmic equation to be defined, x > -9, so x≠ -25
Thus, the only solution is x = -5.
7 0
3 years ago
You have a stack of 99 different books, and you are putting them all on your shelf. How many different ways are there for you to
Tanzania [10]

Answer:

9.332622\times 10^{155}

Step-by-step explanation:

Before getting the final result, let's analyse the same situation but with less books for having a better perspective. For example, just 3 books, named: A, B and C

3 books mean 3 spaces

At the beginning, the first space has 3 ways to be occupied: they are book A, B or C.

If the first place is already occupied for any of them, then, the second place could be occupied just by the two others. If the second place is occupied by any of those two, finally, the third space just could be occupied by one.

Imagine that first space is occupied by book A. The ways to arrange the other books would be:

  1. Book A ----- Book B ----- Book C
  2. Book A ----- Book C ----- Book D

As you see, there are two ways to arrange them positioning the book A at the beginning. The same would happen with book B and book C at the beginning. It means there are 3 options at the beginning and then just 2.

If we multiply those values we get the total ways. It means 6 ways.

Real Problem

Now, for the 99 different books the analysis would be the same:

At the beginning would be 99 books to put in the first space, then in the second space would be 98, then 97, then 96, and so on, until 1.

But it is not a problem because there is a way to write it. It is called factorial.

99! = 99\times 98\times 97\times 96\times ...\times 3\times 2\times 1

If we make all this multiplication we get 9.332622\times 10^{155} ways to order the 99 books.

8 0
4 years ago
Complete the inequality.<br> شده از
Lilit [14]

Answer:

breads

Step-by-step explanation:

idk

4 0
3 years ago
Explore special parallelograms by following
DanielleElmas [232]

Answer:

1.) The diagonal lengths are equal

2.) The diagonals are perpendicular

Step-by-step explanation:

I don't have one sorry :(

8 0
3 years ago
What is 6002310.583 in word form?
Pani-rosa [81]
<span>6 002 310.583

Six million and two thousand three hundred and ten point five eight three.
</span>
5 0
3 years ago
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