The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
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Answer:
x = (9/2)√2
Step-by-step explanation:
The ratio of leg x to the hypotenuse 9 is equal to the cosine of 45 degrees:
cos 45 degrees = x/9
To find the value of x, multiply both sides of this equation by 9, obtaining 9*cos 45 degrees, which comes out to x =9(1/√2). Rationalizing the denominator, we get x = (9/2)√2
Y = mx + b, where m = slope = rise/run and b, the y intercept value
m = 1/1 = 1, then y = x + b.
We notice that y intercept is = - 1
And the equation is:
y = x - 1
There are enough information's already given in the question. Based on those information's that answer can be easily deduced.
Radius of the sphere = 8 units
Then
Surface area of the sphere = 4 *pi * r^2
= 4 * pi * (8)^2
= 4 * pi * 64
= 256pi
I hope that this answer has come to your help.
Answer:
Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f brainliest ?
