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yanalaym [24]
3 years ago
15

Find the value of Sin^-1(tan π/4).

Mathematics
1 answer:
zvonat [6]3 years ago
8 0

Answer:

D

Step-by-step explanation:

1. Remind that

\tan \left(\dfrac{\pi }{4}\right)=1.

Here you can use trigonometric table to find the value of \tan\left(\dfrac{\pi}{4}\right), or you can remind that \dfrac{\pi}{4}=45^{\circ} and \tan45^{\circ}=1 because special right triangle 45°-45°-90° is isosceles (with congruent oppposite and adjacent legs) and the ratio between the opposite leg and adjacent leg is equal to 1.

2. Now

\sin^{-1}\left(\tan\left(\dfrac{\pi}{4}\right)\right)=\sin^{-1}1=\dfrac{\pi}{2},

because

\sin\dfrac{\pi}{2}=1.

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Um. i’m pretty sure it’s just 30 feet
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3 years ago
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Do the ratios 42/56 and 56/64 form a proportion?<br> if they do explain your answer
Volgvan
Lets check...

42/56 = 56/64
cross multiply
(56)(56) = (42)(64)
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42/56 = 3/4
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4 0
3 years ago
Find the midpoint of the line segment joining the points (-3,-2) and (-7,5)
Mumz [18]

Answer:

The midpoint is (-5,1.5)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2

( -3+-7)/2 = -10/2 = -5

To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2

( -2+5)/2 = 3/2 = 1.5

The midpoint is (-5,1.5)

7 0
3 years ago
Fie O centrul unui cerc si doua unghiuri la centru adiacente AOB si BOC.Stiind ca masura unghiului AOB = 120 si masura BOC= 150,
kodGreya [7K]

<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution

Given the above information;
AC=AB, therefore ABC is an isosceles triangle. 
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60


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3 years ago
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Step-by-step explanation:

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