Answer:
See explanation
Step-by-step explanation:
Given the equation:

Separate variables
and
:
![2x\sin (2y)dx=(x^2+12)\cos y dy\\ \\\dfrac{2x\sin (2y)dx}{x^2+12}=\cos ydy\ [\text{Divided by non-zero expression }x^2+12]\\ \\\dfrac{2x}{x^2+12}dx=\dfrac{\cos y}{\sin (2y)}dy\ [\text{Divided by }\sin (2y)]\\ \\\dfrac{2x}{x^2+12}dx=\dfrac{\cos y}{2\sin y\cos y}dy\ [\text{Use formula }\sin (2y)=2\sin y\cos y]\\ \\\dfrac{2x}{x^2+12}dx=\dfrac{1}{2\sin y}dy\ [\text{Simplify when }\cos y\neq 0]](https://tex.z-dn.net/?f=2x%5Csin%20%282y%29dx%3D%28x%5E2%2B12%29%5Ccos%20y%20dy%5C%5C%20%5C%5C%5Cdfrac%7B2x%5Csin%20%282y%29dx%7D%7Bx%5E2%2B12%7D%3D%5Ccos%20ydy%5C%20%5B%5Ctext%7BDivided%20by%20non-zero%20expression%20%7Dx%5E2%2B12%5D%5C%5C%20%5C%5C%5Cdfrac%7B2x%7D%7Bx%5E2%2B12%7Ddx%3D%5Cdfrac%7B%5Ccos%20y%7D%7B%5Csin%20%282y%29%7Ddy%5C%20%5B%5Ctext%7BDivided%20by%20%7D%5Csin%20%282y%29%5D%5C%5C%20%5C%5C%5Cdfrac%7B2x%7D%7Bx%5E2%2B12%7Ddx%3D%5Cdfrac%7B%5Ccos%20y%7D%7B2%5Csin%20y%5Ccos%20y%7Ddy%5C%20%5B%5Ctext%7BUse%20formula%20%7D%5Csin%20%282y%29%3D2%5Csin%20y%5Ccos%20y%5D%5C%5C%20%5C%5C%5Cdfrac%7B2x%7D%7Bx%5E2%2B12%7Ddx%3D%5Cdfrac%7B1%7D%7B2%5Csin%20y%7Ddy%5C%20%5B%5Ctext%7BSimplify%20when%20%7D%5Ccos%20y%5Cneq%200%5D)
Now,


Find the constant solutions, if any, that were lost in the solution of the differential equation:
When

then

Answer: 44%
Step-by-step explanation: First, let's add up all the children in the classroom...
15 + 12 = 27
There's 15 boys, therefore have to divide 15 by 27...
15 ÷ 27 = 0.55 x 100 = 55%
Now, let's divided the total amount of girls...
12 ÷ 27 = 0.44 x 100 = 44%
44 + 55 = 99%
The perecent of girls in the classroom are 44%, I hope this helps!
Answer:
$6.50/per pair of socks
Step-by-step explanation:
12*5=60
125-60=65
65/10=6.50
6 : 2 = 8 : x
<span>=> x = 8/ ( 6 /2 ) </span>
<span>=> x = 8/3 </span>
<span>=> 6x = ( 8/3) * 6 = 8 * 2 = 16
</span>
Answer: D) 6x=16
Answer:
Step-by-step explanation:
Dad: 42
Mom: 38
Sister: 15
Tito: 13
Twin 1: 6
Twin 2: 6
(15+13)/2 = 28/2= 14 years old