g Suppose you are rasterizing a triangle with vertices (1, 1), (5, 1), and (2, 9), and the intensity values (e.g., redness) of t
hose vertices are 5, 9, and 14, respectively. Using the linear interpolation scheme, what is the intensity value of an interior point at (3, 5)? Show all your work.
1 answer:
Answer:
6.333
Step-by-step explanation:
Our triangle vertices are
(1,1)(5,1)(2,9)
We are to perform interpolation at point(3,5)
x and y values are interpolated
On vertices (5,1)(2,9)
x = 3
x1 = 5
X2 = 2
Y1 = 1
Y2 = 9
Formula for interpolation
Y = [y1+(x-x1)(y2-y1)]/x2-x
Y = 1+(3-5)(9-1)/2-5
Y = 1+[-2*8/-3]
Y = 1+16/3
From here we use use LCM to get:
19/3 = 6.333
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Answer:
9 inches of rainfall produces the maximum number of gnats.
Step-by-step explanation:
Given :
To Find :How many inches of rainfall produces the maximum number of gnats?
Solution:
G(x) =The number of gnats in millions.
x denotes the length of rainfall
To Find the maximum length find the mid point of zeroes .Since parabolas are symmetrical, the x value of the max falls 1/2 way between the zeros.
So, x = 0 , x= 18
Now Formula of midpoint :
Hence 9 inches of rainfall produces the maximum number of gnats.