What’s an equation of a line that’s perpendicular to 4x-16y=-8 and passes through the point (-3,3)

Mathematics

2 answers:

Diano4ka-milaya [45]2 years ago

4 0

Answer: 4x - 16y = -60

elena55 [62]2 years ago

3 0

Let's first convert the equation of the line given to slope-intercept form:

$y=\frac{1}{4}x +\frac{1}{2}$

We know that the slope (m in y = mx + b) is 1/4. A perpendicular line always has a negative reciprocal slope. So, the equation of the perpendicular line in slope-intercept form is simply:

$y= -4x + \frac{1}{2}$

But, since they give us two points on the line, we'll put that equation in point-slope form (y - k = m(x - h)):

$y - 3 = -4(x+3)$

So, your final answer is y - 3 = -4(x + 3).

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Dovator [93]

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Triangle FGH has the following side lengths: FG = 5 ft, GH = 10 ft, HF = 12 ft Triangle PQR is similar to triangle FGH. The long

7nadin3 [17]

The first thing we must do for this case is find the scale factor.
We have then that for the larger side of both triangle, the scale factor is:
$k = \frac{RP}{HF}$
$k = \frac{7.2}{12}$
$k = 0.6$
To find the other two sides, we must apply the scale factor on each side of the triangle FGH.
We have then:

For PQ
$PQ = k * FG

PQ = 0.6 * 5

PQ = 3$

For QR
$QR = k * GH

QR = 0.6 * 10

QR = 6$

Answer:
You have that the lengths for the other two sides of triangle PQR are:
$PQ = 3

QR = 6$