Question

What’s an equation of a line that’s perpendicular to 4x-16y=-8 and passes through the point (-3,3)

Answer 1

Answer: 4x - 16y = -60

Answer 2

Let's first convert the equation of the line given to slope-intercept form:

$y=\frac{1}{4}x +\frac{1}{2}$

We know that the slope (m in y = mx + b) is 1/4. A perpendicular line always has a negative reciprocal slope. So, the equation of the perpendicular line in slope-intercept form is simply:

$y= -4x + \frac{1}{2}$

But, since they give us two points on the line, we'll put that equation in point-slope form (y - k = m(x - h)):

$y - 3 = -4(x+3)$

So, your final answer is y - 3 = -4(x + 3).