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3 years ago

Factor completely. 2x^4+4x^3-30x^2

Mathematics

1 answer:

kramer3 years ago

7 0

Answer:

Step-by-step explanation:

2x⁴ + 4x³ - 30x² = 2x²*(x² + 2x - 15)

x² + 2x - 15

Sum = 2

Product = -15

Factors = 5 ; (-3)

x² + 2x - 15 = x² + 5x - 3x - 3 *5

= x(x + 5) - 3(x + 5)

= (x + 5)(x - 3)

2x⁴ + 4x³ - 30x² = (2x²) (x + 5)(x - 3)

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Which of the following expressions shows the distributive property applied to the expression below?

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Answer:

C. (z×6)+(z×35)

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2 years ago

Ann increased the quantities of all the ingredients in a recipe by 60\%60%60, percent. She used 808080 grams (\text{g})(g)left p

kari74 [83]

Answer:

50 grams

Step-by-step explanation:

Let the amount of cheese required by the recipe be "x"

Ann increased 60% from original amount and then used up 80 grams. Thus:

Original, increased by 60%, became 80

This translated to algebraic equation would be:

x + 0.6x = 80

Note: 60% = 60/100 = 0.6

So we can solve the above equation for "x" and get our answer. Shown below:

$x + 0.6x = 80\\1.6x=80\\x=\frac{80}{1.6}\\x=50$

Hence,

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2 years ago

mrs. lbare wrote three decimals on the bored follwed by the two blank spaces. Complete the sequence of numbers

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The rest of the sequence might be 10.5, 12.45, 14.10

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3 years ago

Printer A can print 30 pages per minute. Printer B can print 40 pages per minute. Printer B begins printing 3 minutes after Prin

anzhelika [568]

Printer A prints for 10 minutes, so prints

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3 years ago

In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat

monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

$f(t) = 10000(0.9407)^t$

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

$f(t) = f(0)(1-r)^t$

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that $f(0) = 10000$ , thus:

$f(t) = 10000(1-r)^t$

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

$f(2) = 8850$

We use this to find 1 - r.

$f(t) = 10000(1-r)^t$

$8850 = 10000(1-r)^2$

$(1-r)^2 = \frac{8850}{10000}$

$(1-r)^2 = 0.885$

$\sqrt{(1-r)^2} = \sqrt{0.885}$

$1 - r = 0.9407$

Thus

$f(t) = 10000(1-r)^t$

$f(t) = 10000(0.9407)^t$

7 0

2 years ago