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3 years ago

The boiling point of water is 100.00 °C at 1 atmosphere.

Chemistry

1 answer:

Oksana_A [137]3 years ago

4 0

Answer:

The solution's boiling point is 100,2°C and its molality is 0,13 m

Explanation:

This is the colligative propertie about elevation of boiling point

ΔT = Kb . m . i where

ΔT is the difference between T° at boiling point of the solution - T° at boiling point of the solvent pure

Kb means ebulloscopic constant (0,52 °C.kg/m .- a known value for water)

m means molality (moles of solute in 1kg of solvent)

i means theVan 't Hoff factor ( degree of dissociation for a compound)

IT HAS NO UNITS

NiI2 ---> Ni2+ + 2I- (we have 1 Ni2+ and 2 I-), the i for this, is 3

The 11,11 g of the salt are in 272,2g of water but I need to know how many mass of the salt is in 1000 g of water (1000 g is 1 kg) so the rule of three is:

272,2g ____ 11,11g

1000g _____ (1000 g . 11,11g) / 272,2g = 40,81g

As the molar mas of NiI2 is 312.5 g/mol, the moles of salt are, mass/molar mass, 40,81g /312.5 g/mol = 0,130 moles

T° of b p sl - 100°C = 0,52 °C.kg/m . 0,130 m/kg . 3

T° of boiling point solution = (0,52 °C.kg/m . 0,130 m/kg . 3) + 100°C

T° of boiling point solution = 100,2°C

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Need help with 14 and 16 pls asap!! this is my friends test and im taking it tomorrow!!

marin [14]

Answer:

Q14: 17,140 g = 17.14 kg.

Q16: 504 J.

Explanation:

Q14:

To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).

m is the mass of the ice (m = ??? g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).

∵ Q = m.c.ΔT

∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)

∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.

Q16:

To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 12.0 g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).

∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.

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3 years ago

Difference between a row (“period”) & a column (“group”) on the periodic table and examples.

saw5 [17]

The rows are the one line of elements that goes from left to right horizontally. A column is a line of elements that goes vertically.

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Identify reagents necessary to convert cyclohexane into 1,3-cylohexadiene: notice that the starting material has no leaving grou

Vinvika [58]

1,3-cylohexadiene i synthesized starting from cyclohexane in following 4 steps.

1) Free Radical Substitution Rxn: Halogenation of cyclohexane in the presence of UV yield chlorocyclohexane.

2) Elimination Rxn: Dehydrohalogenation of chlorocyclohexane yields cyclohexene.

3) Halogenation of Cyclohexene (Electrophillic Addition Rxn) gives 1,2-dihalocyclohexane.

4) Elemination Rxn: When dibromocyclohexane is treated with KOH and heated it gives 1,3-cyclohexadiene as shown below,

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3 years ago

Convert 150 kPa to atmospheres. *

lakkis [162]

Answer: 1.48 atmosphere

Explanation:

Pressure in kilopascal = 150

Pressure in atmosphere = ?

Recall that 1 atmosphere = 101.325 kilopascal

Hence, 1 atm = 101.325 kPa

Z atm = 150 kPa

To get the value of Z, cross multiply

150 kPa x 1 atm = 101.325 kPa x Z

150 kPa•atm = 101.325 kPa•Z

Divide both sides by 101.325 kPa

150 kPa•atm/101.325 kPa = 101.325 kPa•Z/101.325 kPa

1.48 atm = Z

Thus, 150 kPa is equivalent to 1.48 atmospheres

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