All categories

3 years ago

What is the limiting reactant in the following equation? How much Fe2O3 will be produced if 2.1 g of Fe with 2.1 g of O2?

Chemistry

1 answer:

Verizon [17]3 years ago

8 0

Answer:

Fe is limiting, and it will produce .0188 mols of Fe2O3

Explanation:

after you convert both Fe and O2 to mols by using their molar mass, you see there is less Fe than O2 so that is your limiting reactant. To find the amount of Fe2O3 you devide the limiting reactant by it's coefeciant (4) then multiply it by the products coefficant (2). Let me know if you have any questions

You might be interested in

What is the reaction type 2 Mgl2+ Mn(SO3)2 → 2 MgSO3 + Mnl4

Oksana_A [137]

Answer:

The reaction type is double displacement

4 0

2 years ago

Irony can be seen in which of the following lines? (Mark all that apply.)

Flura [38]

Answer:

Awnser Is B

Explanation:

5 0

3 years ago

Hypothesis of 6. You decide to clean your bedroom. You notice that your floor is covered with clothes.

ZanzabumX [31]

Answer: So you could for example say, “IF I through my clothes into the closet. THEN the floor will be visible” I capatlized if and then because you need them in a hypothesis.

Explanation:

6 0

3 years ago

I have attached all the problems, but really if you just do one so I understand how to do it, that would be great!

Ivahew [28]

Answer:

Answer of question a is 345J.

Explanation:

In question a following is given in data:

-mass of iron (m) = 10.0 g

-temperature (ΔT) = final temperature- initial temperature= 100-25= 75 degree Celsius

-Specific Heat capacity of iron (c)= 0.46J/g°C.

Heat (Q)=?

Solution:

Formula for Heat is :

Q=m x c x ΔT

Q= 10 x 0.46 x 75

Q= 345 J.

so, 345 joules of heat is needed to increase the temperature of 10 grams of iron.

From the above formula all other questions can easily be solved from the same procedure.

4 0

3 years ago

How many atoms are found in 3.45g of CO2?

USPshnik [31]

Answer: The number of carbon and oxygen atoms in the given amount of carbon dioxide is $4.72\times 10^{22}$ and $9.44\times 10^{22}$ respectively

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of carbon dioxide gas = 3.45 g

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in above equation, we get:

$\text{Moles of carbon dioxide gas}=\frac{3.45g}{44g/mol}=0.0784mol$

1 mole of carbon dioxide gas contains 1 mole of carbon and 2 moles of oxygen atoms.

According to mole concept:

1 mole of a compound contains $6.022\time 10^{23}$ number of molecules

So, 0.0784 moles of carbon dioxide gas will contain $1\times 0.0784\times 6.022\times 10^{23}=4.72\times 10^{22}$ number of carbon atoms and $2\times 0.0784\times 6.022\times 10^{23}=9.44\times 10^{22}$ number of oxygen atoms

Hence, the number of carbon and oxygen atoms in the given amount of carbon dioxide is $4.72\times 10^{22}$ and $9.44\times 10^{22}$ respectively

3 0

3 years ago