Question

Question 19 (1 point)

Answer 1

The equation of line perpendicular to given line passing through (8,-5) is:

$y = -\frac{3}{4}x +1$

Step-by-step explanation:

Given equation of line is:

$4x-3y = 15\\3y = 4x -15\\\frac{3y}{3} = \frac{4x-15}[3}\\y = \frac{4}{3}x - \frac{15}{3}\\ y = \frac{4}{3}x - 5$

Let m1 be the slope of given line

then

m1 = 4/3

Let m2 be the slope of line perpendicular to given line

As we know that the product of slopes of two perpendicular line is -1

$m_1.m_2 = -1\\\frac{4}{3} . m_2 = -1\\m_2= -\frac{3}{4}$

Equation of line is given by:

$y = m_2x+b$

Putting the value of the slope

$y = -\frac{3}{4}x +b$

Putting the point (8,-5) in equation

$-5 = -\frac{3}{4} (8) +b\\-5 = -3 * 2 +b\\-5 = -6 +b\\b = -5+6\\b = 1$

Putting the value of b in equation

$y = -\frac{3}{4}x +1$

Hence,

The equation of line perpendicular to given line passing through (8,-5) is:

$y = -\frac{3}{4}x +1$

Keywords: Equation of line, slope

Learn more about equation of line at:

• brainly.com/question/570757
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