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Zina [86]
3 years ago
15

Which phrase represents this expression? 6×(5+2) Select each correct answer. 2 more than the product of 6 and 5 6 multiplied by

the product of 5 and 2 the total of 5 and 2 is multiplied by 6 the product of 6 and the sum of 5 and 2
Mathematics
1 answer:
Whitepunk [10]3 years ago
5 0

Answer:

a and c

Step-by-step explanation:

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Pamela is 7 years older than Jiri. The sum of their ages is 47. What is Jiri's age?
PolarNik [594]
Jiri is 20 years old
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3 years ago
Pls can solve this question . thanks
Lemur [1.5K]
The answer is 75

explanation: 180cm divided by 45 cm is 4, so 300cm divided by 4 is 75
7 0
2 years ago
A manager randomly selected 25 large cash transactions at a bank that were made in January. The manager then carefully tracked d
Dmitriy789 [7]

Answer:

0.4629 = 46.29% probability that the manager finds more than two such transactions

Step-by-step explanation:

For each transaction, there are only two possible outcomes. Either there is a procedural error, or there is not. The probability of a procedural error on a transaction is independent of any other transaction. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A manager randomly selected 25 large cash transactions at a bank that were made in January.

This means that n = 25

The chance for a procedural error is 10%

This means that p = 0.1

What is the probability that the manager finds more than two such transactions?

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718

P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994

P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659

P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0718 + 0.1994 + 0.2659 = 0.5371

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5371 = 0.4629

0.4629 = 46.29% probability that the manager finds more than two such transactions

4 0
3 years ago
Fill in the missing coefficients in the expansion of the binomial (2x^2+y^2)^4
Helga [31]
The expansion of the binomial:
( 2 x² + y² ) ^4 = 
(2 x^{2} ) ^{4} + 4 * (2 x^{2} ) ^{3}* y^{2} + 6 * ( 2 x^{2} ) ^{2}*( y^{2}) ^{2}  +4*2 x^{2} *( y^{2}) ^{3}+( y^{2}) ^{4}=
=16 x^{8}+32 x^{6} y^{2}+24 x^{4}  y^{4}  + 8  x^{2}  y^{6}+ y^{8}
6 0
3 years ago
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He subtracted instead of added

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3 years ago
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