Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
If this is in value, you would have $5,060. If you mean bills it would be 560.
To start, we need to distribute
multiply 2x by <em>everything</em> in the parenthesis
2x (5 + 3x) - x
2x × 5 = 10x
2x × 3x = 6x²
now we have...
10x + 6x² - x
<em>simplify </em>
<u>6x² + 9x </u>
the coefficient of x is 9!
For the restaurant to make 20 gallons of a lemonade mixture that is 10% sugar, they need 12 gallons of the 12% lemonade and 8 gallons of the 7% lemonade. The correct answer is A.
2 3/4+1 5/8= deducted amount of apples
improper fraction= 11/4+13/8
same denominator= 2(11/4)+13/8
<span>2(11/4)+13/8=22/8+13/8=35/8=4 3/8</span>
6 1/2- 4 3/8
improper fraction= 13/2-35/8
same denominator= 4(13/2)-35/8
52/8-35/8= 17/8 lbs. There u go!
