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4 years ago

Please need help on B

Mathematics

1 answer:

MA_775_DIABLO [31]4 years ago

4 0

The LCD of 1/2 and 5/6 is equal to the LCM of 2 and 6.

Multiples of 2 and 6
2: 2,4,6
6: 6,12,18

As you can see, the first number in both lines are 6.

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Give an example of an experiment where a control group would not be necessary.

Nataly [62]

DoE studies, for example do not require control group, since they usually involve models in which the number of variables are substantially smaller than the number of experiments. The DoE analysis provides a description model that shows how the responses or output variables depend on the factor settings or input variables. As long as the unknowns are substantially less than the number of equations, there is very minimal risk of over-fitting.

8 0

3 years ago

Which expression is equivalent to 8 x minus 12 y + 32?

NeX [460]

Set each answer up equal to the question, solve and see if the two numbers you end up with are equal, if not try the next answer!

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3 years ago

What is the area of sector?

Shtirlitz [24]

Answer:

Step-by-step explanation:

since 90 degrees is 1/4 of a circle, the area of the sector is 5²pi/4 = 25/4pi = 19.63

5 0

3 years ago

Is this a quadratic function 2x+13=13

lys-0071 [83]

Answer:

Step-by-step explanation:

Simplifying

2x + 13 = 0

Reorder the terms:

13 + 2x = 0

Solving

13 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.

13 + -13 + 2x = 0 + -13

Combine like terms: 13 + -13 = 0

0 + 2x = 0 + -13

2x = 0 + -13

Combine like terms: 0 + -13 = -13

2x = -13

Divide each side by '2'.

x = -6.5

Simplifying

x = -6.5

7 0

2 years ago

PLEASE HELP!!!

tatuchka [14]

Asked and answered elsewhere.
brainly.com/question/10629871

How do you calculate it? You start by expressing the density in the units you have. Then you multiply by appropriate conversion factors to get to the units you want. Treat units as though they were any other variable. A value cancels that appears in both the numerator and denominator of a fraction.

$\dfrac{56.15\,kg}{0.222\,hh}\cdot \dfrac{1000\,g}{1\,kg}\cdot \dfrac{1\,pw}{1.55\,g}\cdot \dfrac{1\,hh}{238.5\,L}\cdot \dfrac{9.091\,L}{1\,pk}\\\\=\dfrac{56.15\cdot 1000\cdot 9.091\,pw}{0.222\cdot 1.55\cdot 238.5\,pk}\\\\ \approx6220\,\frac{pw}{pk}$

5 0

3 years ago