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Arte-miy333 [17]
3 years ago
15

PLEASE HELP!!!

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0
Asked and answered elsewhere.
brainly.com/question/10629871

How do you calculate it? You start by expressing the density in the units you have. Then you multiply by appropriate conversion factors to get to the units you want. Treat units as though they were any other variable. A value cancels that appears in both the numerator and denominator of a fraction.

\dfrac{56.15\,kg}{0.222\,hh}\cdot \dfrac{1000\,g}{1\,kg}\cdot \dfrac{1\,pw}{1.55\,g}\cdot \dfrac{1\,hh}{238.5\,L}\cdot \dfrac{9.091\,L}{1\,pk}\\\\=\dfrac{56.15\cdot 1000\cdot 9.091\,pw}{0.222\cdot 1.55\cdot 238.5\,pk}\\\\ \approx6220\,\frac{pw}{pk}
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I need help please I don't not understand this is getting on my nerves.
Mariulka [41]

Answer:

24,748

Step-by-step explanation:

538

<u>x 46</u>

3228

<u>21520</u>

24748

3 0
3 years ago
How do you solve interquartile range?
77julia77 [94]
By Hand
Step 1: 
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2: 
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3: 
Place parentheses around the numbers above and below the median. 
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4: 
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7),  9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.

Step 5: 
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
5 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through the points (4,5) &amp; (-3, -1)
klemol [59]

Answer:

y=6/7x+11/7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-5)/(-3-4)

m=-6/-7

m=6/7

y-y1=m(x-x1)

y-5=6/7(x-4)

y=6/7x-24/7+5

y=6/7x-24/7+35/7

y=6/7x+11/7

8 0
3 years ago
Answer the following question with explanation
GREYUIT [131]

Answer:

a . 9.66 cm

Step-by-step explanation:

a. rule MDAS

multiple first

4(1)=4

4(√2)=5.66

(4+5.66)=9.66cm

3 0
3 years ago
According to a survey, 29% of people carry at least 1 reusable water bottle. If 5 people are selected randomly, what is the prob
Nitella [24]

Answer:

0.4 is the probability that at least 2 out of 5 will be carrying a reusable water bottle

Step-by-step explanation:

We are given the following information:

We treat people carrying at least 1 reusable water bottle as a success.

P(people carry at least 1 reusable water bottle) = 29% = 0.29

Then the number of people follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 5

We have to evaluate:

P(x \geq 2) =1- P(x < 2) \\=1 - \binom{5}{0}(0.29)^0(1-0.29)^5 + \binom{5}{1}(0.29)^1(1-0.29)^4\\=1- 0.1804 - 0.3684\\= 0.4512\\\approc 0.4

0.4 is the probability that at least 2 out of 5 will be carrying a reusable water bottle

6 0
3 years ago
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