Answer:
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
Answer:
Option D is correct.
VS = 20 units.
Step-by-step explanation:
The complete question is contained in the attached image to this answer.
From the image attached and the additional information about the triangles, it is evident that that triangle VSW is similar to triangle QSR.
Hence, we can write the ratio as
(VS/QS) = (VW/QR)
VS = 2a
QS = 2 × VS = 2 × 2a = 4a
VW = 2a - 2
QR = 3a + 6
(2a)/(4a) = (2a - 2)/(3a + 6)
Cross multiplying,
2a (3a + 6) = 4a (2a - 2)
3a + 6 = 2 (2a - 2)
3a + 6 = 4a - 4
4a - 3a = 6 + 4
a = 10
VS = 2a = 20 units.
Hope this Helps!!!
