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2 years ago

Which of the following graphs is a polynomial function with x-intercepts of (-2, 0), (0, 0), and (3, 0)?

Mathematics

1 answer:

Sergio [31]2 years ago

8 0

Answer:

The intercepts of the third degree polynomial corresponds to the zeros of the equation

y = d*(x-a)*(x-b)(x-c)

Where a, b and c are the roots of the polynomial and d an adjustment coefficient.

y = d*(x+2)*(x)*(x-3)

Lets assume d = 1, and we get

y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x

We graph the equation in the attached file.

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Solve 3x - 4 ≤ 2 or 2x + 11 ≥ -1.<br> {x | x ≤ 2}<br> {x | -6 ≤ x ≤ 2}<br> {all reals}

spayn [35]

3x - 4 < = 2
3x < = 2 + 4
3x < = 6
x < = 6/3
x < = 2

2x + 11 > = -1
2x > = -1 - 11
2x > = -12
x > = -12/2
x > = -6

however, since ur inequality has " or " instead of " and " .....ur answer I believe is going to be {x | x < = 2}

4 0

3 years ago

Write an expression using the distributive property to find the product of 7×63

Nataliya [291]

7*(60+3)=7*60+7*3= 420+21=441

4 0

3 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

11 months ago

John is looking at the eagle on top of a building The height of the building is 120 ft Approximately how many feet is Jack away

bearhunter [10]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. A similar question is attached and is solved.

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are scalene, acute, obtuse, isosceles, equilateral and right angled triangle.

A right angled triangle is a triangle with one angle equal to 90 degrees. The longest side of a right angled triangle is known as the hypotenuse. Trigonometric identities is used to show the relationship between the angles and sides of a right angled triangle, i.e.:

sinθ = opposite/hypotenuse; cosθ = adjacent / hypotenuse; tanθ = opposite / adjacent

From the image:

let the distance from jack to the base of the building be x, hence:

tan60 = x / 60

x = 60 * tan60 = 104 ft.

8 0

2 years ago

Find the value of each variable in the parallelogram

wlad13 [49]

Answer:

B= 90

C= 80

D= 100

Step-by-step explanation:

So let’s start with the bottom angles.

We know that the adjacent angles in a parallelogram add up to 180° so our equation would be $(b-10) + (b+10)=180$ . So let’s simplify it b and b are both the same variables so we will get 2b and -10 + 10 is 0 so we get the following equation $2b=180$ .

So now we divide 180 and 2 and we get 90 as b.

So one side will be 100 because of the +10 and the other 90 because of the -10.

Now for the next side.

$d+c=180$

So we know that b+10 is adjacent to c so 180-100 is 80, so 80 is c.

Now for d.

b-10 is 80 so 180-80 is 100, so d is 100.

7 0

3 years ago