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2 years ago

Find the x-intercept and the y-intercept of the line above

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

5 0

Answer:

(a): x-intercept: -4

(b): y-intercept: -1

Step-by-step explanation:

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4.5m + 8 - 2.3m - 3.5

anastassius [24]

Answer:

494235234934-1304039445

Step-by-step explanation:

4r567890e-r0987ytdghcn

6 0

3 years ago

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

4 0

2 years ago

Write the quadratic equation whose roots are 2 and -2, and whose leading coefficient is 4

chubhunter [2.5K]

Answer:

$4x^2-16=0$

Step-by-step explanation:

We want to write the quadratic equation whose roots are 2 and -2, and whose leading coefficient is 4.

Since 2 and -2 are roots, $x+2\\and\\x-2$ are factors of this quadratic function.

The factored form is given as: $a(x-2)(x+2)=0$

Since the leading coefficient is 4, a=4

Therefore the equation becomes:

$4(x-2)(x+2)=0$

Recognize and expand using difference two squares.

$4(x^2-4)=0$

The required equation is:

$4x^2-16=0$

8 0

2 years ago

⊕→QUESTION & ANSWERS IN THE PICTURE ←⊕

Luda [366]

Step 2 should be:

-6x -9x = - 8 - 2

So answer is the last one

In step 2, Ben did not maintain the equality of the equation

4 0

3 years ago

How to change Base 2 111 to base 10

Ira Lisetskai [31]

111₂ = 1•2² + 1•2¹ + 1•2⁰

111₂ = 4 + 2 + 1

111₂ = 7

8 0

2 years ago