All categories

3 years ago

Whats the unit rate 140 mi in 3.5 h

Mathematics

2 answers:

Furkat [3]3 years ago

8 0

40 miles per hour because 140 divided by 3.5 is 40.

Marina CMI [18]3 years ago

3 0

Answer: The unit rate would be 40 mi/hr.

Step-by-step explanation:

Since we have given that

Length = 140 mi

Number of hours = 3.5 hours

We need to find the unit rate.

According to question, it becomes,

$\dfrac{Length}{Number\ of\ hours}$

$\dfrac{140}{3.5}\\\\=40\ mi/hr$

Hence, the unit rate would be 40 mi/hr.

You might be interested in

Find the value of sec(theta°)cos(theta°) for the following values of theta. <br> b. theta = 225

Nesterboy [21]

Answer:

sec(theta°)cos(theta°) = 1

Step-by-step explanation:

given data

(theta°) = 225

to find out

sec(theta°)cos(theta°)

solution

as we know that given equation

(theta°) = 225

cos(theta°) will be

cos(225°) = -0.7071 .................................1

so we know

sec(theta°) = $\frac{1}{cos(theta)}$ ..............2

so put here value of cos(theta°)

sec(theta°) = $\frac{1}{-0.7071}$

sec(theta°) = - 1.4142

sec(theta°)cos(theta°) = -0.7071 × ( - 1.4142 )

sec(theta°)cos(theta°) = 1

so answer is sec(theta°)cos(theta°) = 1

8 0

3 years ago

Find the area of the trapezoid. If the answer is not an integer, leave it in simplest radical form. The figure is not to scale.

Inessa05 [86]

Answer:

$height = \sqrt{ {25}^{2} - {24}^{2} } = \sqrt{49} = 7 \\ are = \frac{48 + 48 + 24}{2} \times 7 = 193536$

6 0

3 years ago

A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?

Travka [436]

Answer:

$area=\frac{85}{4}feet^{2}$

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

$perimeter=18\frac{1}{2}\\\\length=5$

$2(length+width)=perimeter$

Substitute,

$2(5+width)=18\frac{1}{2}$

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

$2(5+width)=\frac{37}{2}$

Inverse operations,

$2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}$

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

$length=5\\\\width = \frac{17}{4}$