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Eduardwww [97]
3 years ago
5

What is 1395^2 plz help

Mathematics
1 answer:
o-na [289]3 years ago
6 0
1,946,025 would be the answer
all you do is multiply 1395x1395
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-12+8yi=3x-i solve for x and y
kodGreya [7K]

Answer:

x = -4 + 8yi/3 + i/3, y = -3xi/8 - 1/8 - 3i/2

3 0
3 years ago
Given the triangle below what would be the measure in degrees of
alexira [117]

Answer:

∠B = 52°

Step-by-step explanation:

Since we know that the sum of all inner angles of the triangle equal to 180°, then we can make the following equation,

5x + 3x + 2x + 20 = 180

10x = 180 - 20

10x = 160

x = 160 / 10

x = 16

Since we know that ∠B = (2x + 20)°, we can calculate the following

∠B = (2x + 20)°

∠B = (2(16) + 20)°

∠B = (32 + 20)°

∠B = 52°

5 0
3 years ago
Do any of you guys know the answer to this problem: 4 2/3 -3 1/3
vazorg [7]
The answer is 4/3 and I checked two times

3 0
3 years ago
Read 2 more answers
Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST<br> -SEE ATTACHMENT-
yuradex [85]

ANSWER

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

EXPLANATION

From the Pascal's triangle,

The coefficients are :

1, 5, 10,10, 5,1

Because of the negative sign, the expansion will alternate sign.

(x - y) ^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}

We now put y=5 into the expansion to get,

(x - 5) ^{5}  =  {x}^{5}  - 5 {x}^{4} (5) + 10 {x}^{3} ( {5}^{2})  - 10 {x}^{2}  ({5})^{3}  + 5x( {5})^{4}  - {5}^{5}

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

3 0
3 years ago
Read 2 more answers
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