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4 years ago

Solve for a. a+0.3=−2

Mathematics

2 answers:

Gala2k [10]4 years ago

6 0

Subtract 0.3 from both sides : a=-2.3

densk [106]4 years ago

5 0

A= -2.3 is the answer

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The number of knots in a particular type of wood has a Poisson distribution with an average of 1.6 knots in 10 cubic feet of the

HACTEHA [7]

Answer:

0.994 = 99.4% probability that a 10-cubic-foot block of the wood has at most 5 knots.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

1.6 knots in 10 cubic feet of the wood.

This means that $\mu = 1.6$

Find the probability that a 10-cubic-foot block of the wood has at most 5 knots.

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.6}*(1.6)^{0}}{(0)!} = 0.202$

$P(X = 1) = \frac{e^{-1.6}*(1.6)^{1}}{(1)!} = 0.323$

$P(X = 2) = \frac{e^{-1.6}*(1.6)^{2}}{(2)!} = 0.258$

$P(X = 3) = \frac{e^{-1.6}*(1.6)^{3}}{(3)!} = 0.138$

$P(X = 4) = \frac{e^{-1.6}*(1.6)^{4}}{(4)!} = 0.055$

$P(X = 5) = \frac{e^{-1.6}*(1.6)^{5}}{(5)!} = 0.018$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.202 + 0.323 + 0.258 + 0.138 + 0.055 + 0.018 = 0.994$

0.994 = 99.4% probability that a 10-cubic-foot block of the wood has at most 5 knots.

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Answer:

Step-by-step explanation:

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Answer:

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3 years ago

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Karolina [17]

Answer:

-2y=-5x=3

Step-by-step explanation:

Make sure every variable is on one side of the equation and you get the answer.

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3 years ago

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Sergeu [11.5K]

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6 is 75% of 8

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