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tiny-mole [99]
3 years ago
10

Please help me with this problem...

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

The probability that they both miss their targets is 1/3

Step-by-step explanation:

In this question, we are trying to calculate the probability that if the captain and the pirate fires the canon in their ships at the same time, they both miss.

We proceed as follows;

Let the probability of the captain hitting the pirate be P(c) = 1/2

The probability of the captain missing is thus ; 1 - 1/2 = 1/2 or 0.5

Let the probability of the pirate hitting the captain be P(r) = 1/3 , the probability of him not hitting the captain is 1-1/3 = 2/3

Now the probability of both of them missing is = probability of the captain missing a fired shot * probability of the pirate missing a fired shot

Hence, we have; 2/3 * 1/2 = 2/6 = 1/3

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4 years ago
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hichkok12 [17]

Answer:

Option D is correct.

Explicit formula for the geometric sequence is, a_n = 64 \cdot (0.5)^{n-1}

Step-by-step explanation:

Geometric sequence states that a sequence of numbers in which the ratio between consecutive terms is constant,

we can write a formula for the nth geometric sequence in the form of:

a_n = a_1r^{n-1} .....[1] where a_1 is the first term and  r is the common ratio between successive term.

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Here, first term (a_1) = 64.

Common ratio(r) = 0.5

Since,

\frac{32}{64} =0.5

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Substitute the value of a and r in [1] we get;

a_n = 64 \cdot (0.5)^{n-1}

therefore, the explicit formula for the geometric sequence is, a_n = 64 \cdot (0.5)^{n-1}


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Answer:

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Step-by-step explanation:

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