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3 years ago

Please help me with this problem...

Mathematics

1 answer:

Leokris [45]3 years ago

4 0

Answer:

The probability that they both miss their targets is 1/3

Step-by-step explanation:

In this question, we are trying to calculate the probability that if the captain and the pirate fires the canon in their ships at the same time, they both miss.

We proceed as follows;

Let the probability of the captain hitting the pirate be P(c) = 1/2

The probability of the captain missing is thus ; 1 - 1/2 = 1/2 or 0.5

Let the probability of the pirate hitting the captain be P(r) = 1/3 , the probability of him not hitting the captain is 1-1/3 = 2/3

Now the probability of both of them missing is = probability of the captain missing a fired shot * probability of the pirate missing a fired shot

Hence, we have; 2/3 * 1/2 = 2/6 = 1/3

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Step-by-step explanation:

Given:

$\dfrac{dV}{dt}=5\:\text{cm}^3\text{/min}$

Find $\frac{dr}{dt}$ when diameter D = 20 cm.

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Taking the time derivative of V, we get

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Solving for $\frac{dr}{dt}$ , we get

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