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Ghella [55]
3 years ago
14

Devin won a tiny bouncy ball at the school carnival. The diameter of the ball is 1.25 inches. To the nearest hundredth of a squa

re inch, what is the surface area of the ball? Use 3.14 for pi
Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

SA = 4.91 in²

Step-by-step explanation:

A ball is a sphere, and the surface area of a sphere is

SA=4\pi r^2

If our diameter is 1.25, the radius is half of that at r = .625

Filling in, we have

SA = 4(3.14)(.625)² and

SA = 4(3.14)(.390625) so

SA = 4.91 in²

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mars1129 [50]

Answer:

1 hour

Step-by-step explanation:

300/6= 50

in one hour he drives 50 miles

so the answer is 1 hour

7 0
2 years ago
Y+4x=10x-6 solve for x
7nadin3 [17]

Answer:

(y-6)/6 = x

Step-by-step explanation:

y+4x=10x-6

Subtract 4x from each side

y+4x-4x=10x-4x-6

y = 6x-6

Add 6 to each side

y +6 = 6x-6+6

y+6 = 6x

Divide by 6

(y-6)/6 = 6x/6

(y-6)/6 = x



8 0
3 years ago
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(5x^2+8x+18)+(11x^2-17x-7)
GuDViN [60]

Answer: 16x^2 - 9x + 11

Step-by-step explanation:

(5x^2+8x+18)+(11x^2-17x-7)

5x^2+8x+18+11x^2-17x-7

16x^2 - 9x + 11

3 0
3 years ago
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solve the following quadratic equation by completing the square. if you need to round to the nearest tenth. x² - 20x = -75
lesantik [10]
The Answer should be either x=15 or x=5 I got both.
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Find the equation of the line containing the points (20,-7) and (10,-2). Type your answer in this order and don't use spaces or
aliina [53]

(\stackrel{x_1}{20}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{20}}}\implies \cfrac{-2+7}{-10}\implies -\cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-\cfrac{1}{2}}(x-\stackrel{x_1}{20}) \\\\\\ y+7=-\cfrac{1}{2}x+10\implies y=-\cfrac{1}{2}x+3

4 0
2 years ago
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