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BartSMP [9]
3 years ago
8

What is the greatest common factor of 32 and 48

Mathematics
2 answers:
Alexeev081 [22]3 years ago
6 0
The factors<span> for </span>32<span> are </span><span><span>−32,−16,−8,−4,−2,−1,1,2,4,8,16,32</span><span>.

</span></span>The factors<span> for </span>48<span> are </span><span><span>−48,−24,−16,−12,−8,−6,−4,−3,−2,−1,1,2,3,4,6,8,12,16,24,48</span>.

List of all the factors for 32 and 48. 

</span><span>32=−32,−16,−8,−4,−2,−1,1,2,4,8,16,32</span> 
<span>48=−48,−24,−16,−12,−8,−6,−4,−3,−2,−1,1,2,3,4,6,8,12,16,24,48

</span>The <span>common factors</span><span> for </span><span>32,48</span><span> are </span><span><span>−16,−8,−4,−2,−1,1,2,4,8,16</span>.</span><span>−16,−8,−4,−2,−1,1,2,4,8,16
</span>
The GCF<span> of numerical </span>factors <span>−16,−8,−4,−2,−1,1,2,4,8,16</span><span> is </span><span>16.

16</span>
Bond [772]3 years ago
4 0
Turn each number into the product of it's prime factors.

32=16x2=2x2x2x2x2=2^5

48=24*2=6x4x2=2x3x2x2x2

Pick the highest number that occurs. In this case it is 2. Now we have to see how many times it appears in both. It appears 5 times in 32 and 4 times in 48. 4 is the highest number of times it appears in the numbers so:

2^4=2x2x2x2=16

The Greatest Common Factor (GCF) of 32 and 48 is 16.
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Step-by-step explanation:

3/14 of 5 is 1.07142857143

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How many quarters are in $375.75?​
DanielleElmas [232]

Answer:

1503 quarters

Step-by-step explanation:

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Volgvan

Given:

The graph of a proportional relationship.

To find:

The constant of proportionality, the value of y when x is 24 and the value of x when y is 108.

Solution:

If y is directly proportional to x, then

y\propto x

y=kx             ...(i)

Where, k is the constant of proportionality.

The graph of proportional relationship passes through the point (5,15).

Substituting x=5 and y=15 in (i), we get

15=k(5)

\dfrac{15}{5}=k

3=k

Therefore, the constant of proportionality is 3.

Substituting k=3 in (i) to get the equation of the proportional relationship.

y=3x              ...(ii)

Substituting x=24 in (ii), we get

y=3(24)

y=72

Therefore, the value of y is 72 when x is 24.

Substituting y=108 in (ii), we get

108=3x

\dfrac{108}{3}=y

36=y

Therefore, the value of x is 36 when y is 108.

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In the probability distribution to the​ right, the random variable X represents the number of marriages an individual aged 15 ye
kodGreya [7K]

The table of the probability is missing, so i have attached it.

Answer:

μ = 0.919

The interpretation of this is that;on the average, an individual aged 15 years or older has been involved in 0.919 marriages.

Step-by-step explanation:

The expected value which is also called mean value is denoted by the symbol μ. It is defined as the sum of the product of each possibility x with it's probability P(x) as the formula;

μ = Σx.P(x) = (0 × 0.272) + (1 × 0.575) + (2 × 0.121) + (3 × 0.027) + (4 × 0.004) + (5 × 0.001)

μ = 0.919

Thus, the interpretation of this is that;on the average, an individual aged 15 years or older has been involved in 0.919 marriages.

5 0
3 years ago
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