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olga_2 [115]
3 years ago
11

This measures how close a biometric reading is to a prerecorded template

Computers and Technology
1 answer:
rjkz [21]3 years ago
5 0

The question above has multiple choices;

<span>a)      </span>Hamming distance

<span>b)      </span>Match percentage

<span>c)       </span>Legacy amount 100.

<span>d)      </span>PDA reading

The answer is a) Hamming distance


Biometric authentications like other technologies are vulnerable to attacks such as spoofing and transmission. Binary template representations in recent research provide significant improvements in efficiency without compromising data accuracy for biometric modalities like iris, fingerprints, and palm prints.

Any binary biometric representation that uses hamming distance and converts it into a privacy preserving secure protocol comparison provides template protection.






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Write a copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *thi
Olin [163]

The following cose will be used to copy assignment operator for CarCounter

<u>Explanation:</u>

Complete Program:

#include <iostream>

using namespace std;

class CarCounter

{

public:

CarCounter();

CarCounter& operator=(const CarCounter& objToCopy);

void SetCarCount(const int setVal)

{

 carCount = setVal;

}

int GetCarCount() const

{

 return carCount;

}

private:

int carCount;

};

CarCounter::CarCounter()

{

carCount = 0;

return;

}

// FIXME write copy assignment operator

/* Your solution goes here */

CarCounter& CarCounter::operator=(const CarCounter& objToCopy)

{

if(this != &objToCopy)

 carCount = objToCopy.carCount;

return *this;

}

int main()

{

CarCounter frontParkingLot;

CarCounter backParkingLot;

frontParkingLot.SetCarCount(12);

backParkingLot = frontParkingLot;

cout << "Cars counted: " << backParkingLot.GetCarCount();

cout << endl << endl;

system("pause");

return 0;

}

5 0
3 years ago
In Python, if var1 = "Happy" and var2= "Birthday" and var3 = (var 1+var2) *2, then var3 stores the string
nordsb [41]

Answer:

The answer is "Option A".

Explanation:

The program to the given question can be given as:

program:

var1 = "Happy" #defining variable var1

var2= "Birthday" #defining variable var2

var3 = (var1+var2) *2 #defining variable var3 and calculate value

print (var3) #print value.

Output:

HappyBirthdayHappyBirthday

In the above python program, three variable is defined, that is var1, var2, and var3, in which variable var1 and var2 we assign a value, that is "Happy" and "Birthday".

In variable var3 we add the value of var1 and var2 variable and multiply by 2. It will print the variable value two times. and other options are not correct that can be defined as:

  • In option B and C, Both variable var1 and var2 print there values two times but in option B var1 value print two time and var2 value print one time only and option C var1 variable value is print only one time and var2 variable value is print two times that's why it is not correct.
  • In option C, Both variable var1 and var2 print there values two times that's why it is not correct.

7 0
3 years ago
Add three methods to the Student class that compare twoStudent objects. One method (__eq__) should test for equality. A second m
shusha [124]

Answer:

class Student(object):

def __init__(self, name, number):

self.name = name

self.scores = []

for count in range(number):

self.scores.append(0)

 

def getName(self):

 

return self.name

 

def setScore(self, i, score):

 

self.scores[i - 1] = score

 

def getScore(self, i):

 

return self.scores[i - 1]

 

def getAverage(self):

 

return sum(self.scores) / len(self._scores)

 

def getHighScore(self):

 

return max(self.scores)

def __eq__(self,student):

return self.name == student.name

 

def __ge__(self,student):

return self.name == student.name or self.name>student.name

 

def __lt__(self,student):

return self.name<student.name

 

def __str__(self):

return "Name: " + self.name + "\nScores: " + \

" ".join(map(str, self.scores))

 

 

def main():

student = Student("Ken", 5)

print(student)

for i in range(1, 6):

student.setScore(i, 100)

print(student)

 

print("\nSecond student")

student2 = Student("Ken", 5)

print(student2)

 

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

 

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

 

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

 

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

 

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

5 0
3 years ago
What was the first computer programming language?
diamong [38]

Answer:

The answer is B.COBOL

Explanation:

I took AP EX quiz.

5 0
2 years ago
It is a function that removes an existing file from the server.
kondaur [170]

Answer: A) remove()

Explanation:

 The remove() function removes an existing file from the server but it does not affect the existing directory and file. We can also ease and remove files in the file handling by using the remove() function. And it is built-in function that removes any type of the data from the function by taking values in the parameter whose values are equal with the passing value in the parameter.

7 0
3 years ago
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