Answer:
When x = 6.
Step-by-step explanation:
WE need to solve the system:
y = - x^2 + 4x + 4
y = -2x + 4
Equating:
- x^2 + 4x + 4 = -2x + 4
0 = x^2 - 4x - 4 - 2x + 4
x^2 - 6x = 0
x(x - 6) = 0
x = 0, 6.
-2.4 + 3.2t
-3.6 - 1.9t + 1.2 + 5.1t
-2.4 + 3.2t Add like terms
65% !
Plz mark as brainliest!
y^3
- y^15-12
two negatives is a positive
