See the attached picture.
First one:
You take 10 + 3 =13 then add 9 then 5. That all equals 27. Then you add 1 for the top part that isn’t labeled because it’s 10 in the bottom then 9 at the top which means it’s 1. Then for the side that’s unlabeled it’s 2 since it’s all 5 then the other side is 3. Answer is 31
Second one:
This one is the same as #1. You add 14+6+3+4 = 27. The long horizontal unlabeled side is 11 bc 14-3 = 11. Then the other side 2. Answer is 30.
Answer:
Total number of ways will be 209
Step-by-step explanation:
There are 6 boys and 4 girls in a group and 4 children are to be selected.
We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.
So the groups can be arranged as
(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)
Now we will find the combinations in which these arrangements can be done.
1 Boy and 3 girls =
=24
2 Boy and 2 girls=
3 Boys and 1 girl = 
4 Boys = 
Now total number of ways = 24 + 90 + 80 + 15 = 209