Answer:
a) 100/15 = 6.6667 = 6 2/3
b) C = T( 6 2/3)
= T (6 + 2/3)
C = 1T x 6 2/3
= 6 2/3 T
We can show T as time at end of equation or start of brackets
The answer is Pier Pressure
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5
Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students
Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students
Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68
Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
Answer: 1/50
Step-by-step explanation:
= 2 * 10^-2 * 2^0
= 2 * 1/10^2 * 1 (2^0=1)
= 2/100
= 1/50
Answer:
¹/₄x - 3 ≥ 2
+ 3 + 3
4(¹/₄x) ≥ 4(5)
x ≥ 20
Step-by-step explanation:
