Question

Solve this plss I need help :c2/3(3х + 9) = - 2(2x + 6)​

Answer 1

Answer:

$x=-3$

Step-by-step explanation:

$\frac{2}{3}\left(3x+9\right)=-2\left(2x+6\right)$

Expand:

$\frac{2}{3} *3x+\frac{2}{3} *9=-2*2x+(-2)(6)$

$2x+6=-4x-12$

Subtract 6 from both sides:

$2x+6-6=-4x-12-6$

$2x=-4x-18$

Add 4x to both sides:

$2x+4x=-4x-18+4x$

$6x=18$

Divide both sides by 6:

$\frac{6x}{6}=\frac{-18}{6}$

$x=-3$

Answer 2

I hope this is helpful. Good luck