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Bess [88]
2 years ago
8

Can someone help me with #2 and #4

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
6 0
A=4 X1.6hxhdhdhdhdhs
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Evaluate the expression 8x2+9y
Sliva [168]

Answer:

34676

Step-by-step explanation:

8 0
3 years ago
Members of a college chemistry department agree to contribute equal amounts of money to make up a scholarship fund of $280. Then
Zarrin [17]

Answer:

7 members

Step-by-step explanation:

Lets say that the department has n members. If each member contributes with an equal amount x and make a total of $280, we know that:

n*x = 280

Where each one colaborated with:

n*x/n = 280/n

Or what is the same that: (as the n on the left eliminate themselves)

x = 280/n (*)

Now the department hires 3 more members, so we now have n+3 members. And we know that the pass from contributing x to contribute $30 less, it is, x-30 (I omit the $ symbol for simplicity). So, know we have:

x-30 = 280/(n+3)

We can replace x here by the formulation of x we did in the (*) equation:

( 280/n) - 30 = 280/(n+3)

using common denominator:

( 280/n) - 30 n/n = 280/(n+3)

( 280 - 30 n)/n = 280/(n+3)

Cross multiplying the denominators:

( 280 - 30 n)*(n+3) = 280*(n)

280n - 30n^2 + 840 - 90n = 280n

Subtracting 280 n in both sides:

30n^2 + 840 - 90n = 0

Dividing both sides by 30:

-n^2 - 3n + 28 = 0

Factorizing this term (you can notice the factor immediately or solving with baskara resolution, I omit the baskara for simplicity):

-(n + 7)(n - 4) =0

So, n is equal to 4 and -7. As we are dealing with people we can not have -7 people, so we keep only n=4.

So, previous the new hiring there were 4 members, now there are 7.

The used to collaborate with 280/4 = $70, now the collaborate with 280/7=$40, and we see the collaboration decreased in $30.

7 0
3 years ago
Please helpppppppppp
bija089 [108]

Answer:

A

Step-by-step explanation:

5 0
2 years ago
205 students enrolled in a freshman-level chemistry class. By the end of the semester, 4 times the number of students passed as
AlexFokin [52]

Answer: 164 students passed and 41 students failed.

Step-by-step explanation:

Let the number of students be x

x students failed, but 4 times the failed students passed.

So 4x students passed and x students failed.

4x + x = 205

5x = 205

x = 205/5

x = 41

41 times 4 is 164 and 41 times 1 is 41.

So 164 students passed and 41 students failed

3 0
2 years ago
F(x)=−1/2(x−2)(x+6)<br><br> rewrite the function in vertex form
Whitepunk [10]

Answer:

tell me this question in a more clearer way then ill message the answer

Step-by-step explanation:

6 0
2 years ago
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