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kupik [55]
3 years ago
15

What transformation transforms (a, b) to (a, −b) ​?

Mathematics
2 answers:
Vlad [161]3 years ago
6 0

Answer:

a reflection over the x-axis

<em>This is the correct answer! Thank you!</em>

mash [69]3 years ago
4 0

Answer:

Reflection over the x-axis

Step-by-step explanation:

The transformation rule for a reflection over the x-axis is (x, -y)

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Leokris [45]

336

Step-by-step explanation:

2021-5=2016÷6=336

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3 years ago
Which expression is equivalent to 8/9 divided by 3/4
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Step-by-step explanation:

Dividing by a fraction is the same as multiplying with the opposite of the fraction. 8/9 / 3/4=8/9×4/3=32/27=1 5/27.

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What is 999 times 100.0​
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PLEASE HELP PRE CAL!!
Len [333]

Answer:

Width = 2x²

Length = 7x² + 3

Step-by-step explanation:

∵ The area of a rectangle is 14x^{4}+6x^{2}

∵ Its width is the greatest common monomial factor of 14x^{4} and 6x²

- Let us find the greatest common factor of 14 , 6 and x^{4} , x²

∵ The factors of 14 are 1, 2, 7, 14

∵ The factors of 6 are 1, 2, 3, 6

∵ The common factors of 14 and 6 are 1, 2

∵ The greatest one is 2

∴ The greatest common factor of 14 and 6 is 2

- The greatest common factor of monomials is the variable with

   the smallest power

∴ The greatest common factor of x^{4} and  x² is x²

∴ The greatest common monomial factor of  14x^{4} and 6x² is 2x²

∴ The width of the rectangle is 2x²

To find the length divide the area by the width

∵ The area = 14x^{4}+6x^{2}

∵ The width = 2x²

∴ The length = ( 14x^{4}+6x^{2}) ÷ (2x²)

∵  14x^{4} ÷ 2x² = 7x²

∵ 6x² ÷ 2x² = 3

∴ ( 14x^{4}+6x^{2}) ÷ (2x²) = 7x² + 3

∴ The length of the rectangle is 7x² + 3

8 0
3 years ago
A falling object accerlates from -10.0m/s to -30.0m/s how much time does that take
Leya [2.2K]

Answer:

2.04 seconds

Step-by-step explanation:

Falling objects near the surface of the earth have an acceleration of -9.81 m/s².

Acceleration is the change in velocity over change in time:

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-9.81 = (-30.0 − (-10.0)) / t

-9.81 = -20.0 / t

t = 2.04

It takes 2.04 seconds.

5 0
3 years ago
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