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3 years ago

Solve m=Y2-Y1/X2-X1 for Y2

Mathematics

2 answers:

Rus_ich [418]3 years ago

7 0

You know this is just a formula, right?

Mashutka [201]3 years ago

6 0

Times both sides by (X2-x1)
m(x2-x1)=y2-y1
add y1 to both sides
m(x2-x1)+y1=y2

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Simplify expressions

charle [14.2K]

<h3>a) $\frac{2}{5} \div ( - \frac{3}{4} )$ </h3><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2> $- \frac{2}{5} \div \frac{3}{4}$ </h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h3>Hence, Quotient = $- \frac{8}{15}$ </h3>

<h3>b) $0.4 \div ( - 0.75)$ </h3><h3>■Convert the decimals into a fractions</h3>

<h2> $\frac{2}{5} \div ( - \frac{3}{4} )$ </h2><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2> $- \frac{2}{5} \div \frac{3}{4}$ </h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h2> $- \frac{8}{15}$ </h2><h3>Hence, Quotient is $- \frac{8}{15}$ </h3>

<h3>c) $- \frac{2}{5} \div \frac{3}{4}$ </h3><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h2> $- \frac{8}{15}$ </h2><h3>Hence, The Quotient is $- \frac{8}{15}$ </h3>

4 0

2 years ago

Need help anyone can help giving brain liest

trapecia [35]

Answer:

14 gel pens/minute

Step-by-step explanation:

divide the amount by time.

210/15 = 14

6 0

3 years ago

Read 2 more answers

Which of the following represents the factorization of the binomial below ? x^2 - 144

Dima020 [189]

It factors to (x+12)(x-12)

This is the same as (x-12)(x+12) as we can multiply two expressions in any order we want. This is like saying 7*5 is the same as 5*7

I used the difference of squares rule to factor x^2 - 144. It might help to write x^2 - 144 as x^2 - 12^2, then compare it to a^2 - b^2 = (a-b)(a+b)

6 0

3 years ago

41:41

Minchanka [31]

Answer:

Answer: B

Step-by-step explanation:

just solve keep up learning!

6 0

3 years ago

Read 2 more answers

A business owner collected data on the people working for her company. She determined the average number of minutes each employe

Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.<em> </em>

Step-by-step explanation:

The following information is missing

<em>A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48. </em>

<em>A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48. </em>

<em>The business owner uses the median and IQR to determine the center and variability of the data sets. Which best describes the comparison? </em>

<em>The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric. </em>

<em>The comparison would be more accurate using the mean and MAD because the median of both data sets is the same. </em>

<em>The comparison using median and IQR is best because one of the graphs is not symmetrical. </em>

<em>The comparison using median and IQR is best because the median is greater than the IQR for both data sets.</em>

<em />

Mean and MAD are useful for comparison when both data sets are symmetrical.

In the women box plot the Q1 is at 34, the median is at 48, and the Q3 is at 50, so it is not symmetrical (the difference between the median and the Q1, and the Q3 and the median is not the same)

8 0

3 years ago