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trapecia [35]
3 years ago
14

Floor tile cost $11 per square yard. how much it cost to tile a bathroom that is 90 square feet

Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0
To convert square feet to square yards divide 9 by the number of square feet (I remember that since there are 3 feet in 1 yard and 9 is 3 squared) so 90/9=10. Multiply the 10 sq yds by the price per sq yd: 10x11=120. It would cost $120 :) I hope this helps :)
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Sain has a student loan for $22,990. This loan has a simple interest rate of 5%. What is the amount of interest Sain will be cha
djyliett [7]

Answer:

3448.5

Step-by-step explanation:

I=PRT

I=22990×0.05×3

=$3448.5

4 0
3 years ago
Read 2 more answers
Solve the equation<br> 0.2(d-6)=0.3d+5-3+0.1d for d
WINSTONCH [101]

Answer:

d= -16

Step-by-step explanation:

To answer this question you'll have to first simplify the equation to

0.2d+-1.2=0.3d+5-3+0.1d

then combining like terms you get

0.2d-1.2=(0.3d+0.1d)+(5+-3)

0.2d-1.2=0.4d+2

then subtract 0.4d from both sides leaving you with

-0.2d-1.2=2

then add 1.2 to both sides

-0.2d=3.2

after you divide both sides by -0.2

leaving you with the answer

D= -16

7 0
3 years ago
Read 2 more answers
Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the
ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}&#10;And in order to find the sample mean we just need to use this formula:&#10;[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0
3 years ago
How can you do this
ololo11 [35]

You add up all of the sides and the numbers that are there you pretend that they are on the other side and just add all of them up correctly and you will get your answer.


3 0
3 years ago
Read 2 more answers
0.5a − 0.3 = 5 (solve for a)
Alla [95]
0.5a - 0.3 = 5

Add 0.3 to both sides:

0.5a = 5.3

Divide both sides by 0.5:

a = 10.6
3 0
3 years ago
Read 2 more answers
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